oddNumberGenerator.go

func oddNumberGenerator(n int) []int {

    vals := make([]int, n);

    origN := n;

    // In PHP I'd do while count($arr) < $n, but as we initialise
    // an array of size n that won't work in go
    for i := 0; n > 0; i++  {
        if (i % 2 == 1) {
            vals[(origN - n)] = i;
            n--;
        }
    }

    return vals;
}

Another possible way of doing it (I don't profess to be a good Gopher, but I find it easier to grok than yours)

func oddNumberGenerator(n int) []int {
    generatedNumbers := make([]int, n)

    // Every sequence starts with one
    generatedNumbers[0] = 1

    // Every other index is the previous one, plus 2
    for i := 1; i < n; i++ {
        generatedNumbers[i] = generatedNumbers[i - 1] + 2
    }

    return generatedNumbers
}

@caius: Aye, that's easier to read than me. I was thinking more generally about the problem though.

e.g.: I need an array of N items that satisfy condition X. Odd numbers seemed like an easy condition to test with, but obviously that can be simplified to [i-1]+2, so doesn't really show off the whole condition based side of pushing into the array