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Through above code while we sharing images or video we getting two option that are feed and stories.I have to open stories directly rather than two option like above code shows.Can we open stories directly.
Hello PasqualePuzio,
Thank you for sharing the post.
We need your help to directly post the story to Instagram on click of share, but we use the above code we are able to see a screen inbetween which asks the user to select the type of post(Instagram Feed/Instagram Story) we dont need this option. Request to help us and share the details to achieve this.
Below are the details
Source code:
Uri backgroundAssetUri = FileProvider.getUriForFile(context, "com.example.provider", imagePath);
Intent feedIntent = new Intent(Intent.ACTION_SEND);
feedIntent.setType("image/*");
feedIntent.putExtra(Intent.EXTRA_STREAM, backgroundAssetUri);
feedIntent.setPackage(Utils.INSTAGRAM_PACKAGE_NAME);
Intent storiesIntent = new Intent("com.instagram.share.ADD_TO_STORY");
storiesIntent.setDataAndType(backgroundAssetUri, "jpg");
storiesIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
storiesIntent.setPackage(Utils.INSTAGRAM_PACKAGE_NAME);
context.grantUriPermission(
Utils.INSTAGRAM_PACKAGE_NAME, backgroundAssetUri, Intent.FLAG_GRANT_READ_URI_PERMISSION);
Intent chooserIntent = Intent.createChooser(feedIntent, context.getString(R.string.social_instagram));
chooserIntent.putExtra(Intent.EXTRA_INITIAL_INTENTS, new Intent[] {storiesIntent});
context.startActivity(chooserIntent);
Its working as I expected. I want to open Screen3 directly after clicked on "Share with instagram" from screen1. I dont want to show screen2.
Please guide me how can I achieve this.
Hi
Hello PasqualePuzio,
Thank you for sharing the post.
We need your help to directly post the story to Instagram on click of share, but we use the above code we are able to see a screen inbetween which asks the user to select the type of post(Instagram Feed/Instagram Story) we dont need this option. Request to help us and share the details to achieve this.
Below are the details
Source code:
Uri backgroundAssetUri = FileProvider.getUriForFile(context, "com.example.provider", imagePath); Intent feedIntent = new Intent(Intent.ACTION_SEND); feedIntent.setType("image/*"); feedIntent.putExtra(Intent.EXTRA_STREAM, backgroundAssetUri); feedIntent.setPackage(Utils.INSTAGRAM_PACKAGE_NAME); Intent storiesIntent = new Intent("com.instagram.share.ADD_TO_STORY"); storiesIntent.setDataAndType(backgroundAssetUri, "jpg"); storiesIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION); storiesIntent.setPackage(Utils.INSTAGRAM_PACKAGE_NAME); context.grantUriPermission( Utils.INSTAGRAM_PACKAGE_NAME, backgroundAssetUri, Intent.FLAG_GRANT_READ_URI_PERMISSION); Intent chooserIntent = Intent.createChooser(feedIntent, context.getString(R.string.social_instagram)); chooserIntent.putExtra(Intent.EXTRA_INITIAL_INTENTS, new Intent[] {storiesIntent}); context.startActivity(chooserIntent);
Its working as I expected. I want to open Screen3 directly after clicked on "Share with instagram" from screen1. I dont want to show screen2.
Please guide me how can I achieve this.
I too want to get the same I researched it a bit but no luck.
If u happen to crack the issue, could you please share the code with us
Simply call startActivity(feedIntent) or with other one intent from the example. But keep in mind to check if Instagram is installed before starting this intent to avoid fatal exception being thrown
Hi @michaeltys, I got a problem when sharing a photo on Instagram.
I using FileProvider.getUriForFile, but this only works when sharing "Direct" or "Story". When sharing on Feed, Instagram app got an error and don't file my file.
Could you please help me, please
Hi @michaeltys, i had same issue with @NALAndrod2
@NALAndrod2 did you find a solution ? I have been searching for this 5 days.
@ysnklcky, Not yet :(. It works normally on android below N with Uri.parse(file.absolutePath). I'm still I am still researching. The document of Instagram developer seems to be too old
Same problem --> https://stackoverflow.com/questions/60826717/android-not-able-to-share-photos-on-instagram-using-intent
Same problem --> https://stackoverflow.com/questions/60786976/share-intent-issue-in-instagram-feed
Same problem --> https://github.com/esysberlin/esys-flutter-share/issues/57
But still no solution. Could you please update, if you found solution.
As this link https://stackoverflow.com/questions/60826717/android-not-able-to-share-photos-on-instagram-using-intent/60832792#60832792.
I guess this issue belongs to Instagram and android 10
Hello guys, any news? I trying to fix this issue from the last week :/
Workaround solution to fix temporary this IG bug (I think is a bug from the Instagram app)
https://stackoverflow.com/questions/60776730/instagram-android-share-intent-unable-to-load-image
Hello,I want to click a picture and post it on instagram using app I have made + I want to include Hastags
You can try this. It worked for me. Directly Instagram story.
private void shareInstagram(Uri uri) {
Intent feedIntent = new Intent(Intent.ACTION_SEND);
feedIntent.setType("image/*");
feedIntent.putExtra(Intent.EXTRA_STREAM, uri);
feedIntent.setPackage(Contracts.INSTAGRAM_PACKAGE_NAME);
Intent storiesIntent = new Intent(Contracts.INSTAGRAM_STORY_ACTION_NAME);
storiesIntent.setDataAndType(uri, "image/*");
storiesIntent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION);
storiesIntent.setPackage(Contracts.INSTAGRAM_PACKAGE_NAME);
this.grantUriPermission(
Contracts.INSTAGRAM_PACKAGE_NAME, uri, Intent.FLAG_GRANT_READ_URI_PERMISSION);
feedIntent.putExtra(Intent.EXTRA_INITIAL_INTENTS, new Intent[]{storiesIntent});
startActivity(feedIntent);
}
Hey @gokmenbayram ........could you please tell me what you actually passed when you call this method ????
@michaeltys, could you please tell me where and how you call your method?? What you pass on the call of this method????
Hey @gokmenbayram ........could you please tell me what you actually passed when you call this method ????
i didnt understand this comment.
Hey @gokmenbayram ...i meant that I understood your shareInstagram(Uri uri method ) but I want to know what you actually passed as uri while calling this method???? Please do let me know..
with provider.
public Uri getImageUri() {
File directory = new File(Files.statisticsSSPath());
File file = new File(directory, 0 + ".png");
return FileProvider.getUriForFile(Application.context(), Application.context().getPackageName() +".provider",file);
}
Is there a way to get a callback that post/story shared successfully?
Is there any way around for react native/expo ?
Thank you. It really helped 🥇