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numpy scipy gaussian elimination using LU decomposition with pivoting
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#! /usr/bin/env python | |
""" | |
Solve linear system using LU decomposition and Gaussian elimination | |
""" | |
import numpy as np | |
from scipy.linalg import lu, inv | |
def gausselim(A,B): | |
""" | |
Solve Ax = B using Gaussian elimination and LU decomposition. | |
A = LU decompose A into lower and upper triangular matrices | |
LUx = B substitute into original equation for A | |
Let y = Ux and solve: | |
Ly = B --> y = (L^-1)B solve for y using "forward" substitution | |
Ux = y --> x = (U^-1)y solve for x using "backward" substitution | |
:param A: coefficients in Ax = B | |
:type A: numpy.ndarray of size (m, n) | |
:param B: dependent variable in Ax = B | |
:type B: numpy.ndarray of size (m, 1) | |
""" | |
# LU decomposition with pivot | |
pl, u = lu(A, permute_l=True) | |
# forward substitution to solve for Ly = B | |
y = np.zeros(B.size) | |
for m, b in enumerate(B.flatten()): | |
y[m] = b | |
# skip for loop if m == 0 | |
if m: | |
for n in xrange(m): | |
y[m] -= y[n] * pl[m,n] | |
y[m] /= pl[m, m] | |
# backward substitution to solve for y = Ux | |
x = np.zeros(B.size) | |
lastidx = B.size - 1 # last index | |
for midx in xrange(B.size): | |
m = B.size - 1 - midx # backwards index | |
x[m] = y[m] | |
if midx: | |
for nidx in xrange(midx): | |
n = B.size - 1 - nidx | |
x[m] -= x[n] * u[m,n] | |
x[m] /= u[m, m] | |
return x | |
if __name__ == '__main__': | |
x = gausselim(np.array([[3, 2], [1, -4]]), np.array([[5], [10]])) | |
print x |
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Hi @sbykl , I think what you're looking for is either
numpy.loadtxt
orpandas.read_csv
. Read the docs, hopefully you'll find usage straightforward. 😃