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CubeSummation
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// 12/27/2015 | |
// Write a function cubeSum(n, m) that will calculate a sum of cubes | |
// of numbers in a given range, starting from the smaller | |
// (but not including it) to the larger (including). | |
// The first argument is not necessarily the larger number. | |
// Examples: | |
// Test.expect(cubeSum(5,0) == 225, "cubeSum(5,0) should be 225"); | |
// Test.expect(cubeSum(2,3) == 27, "cubeSum(2,3) should be 27"); | |
// My Solution: | |
function cubeSum(n, m){ | |
var sum=0; | |
if(n>m){ | |
for(var i=m+1; i<=n;i++){ | |
sum+=i*i*i; | |
} | |
} | |
else{ | |
for(var i=n+1; i<=m;i++){ | |
sum+=i*i*i; | |
} | |
} | |
return sum; | |
} | |
// cubeSum(5,0) | |
// 1^3 + 2^3 + 3^3 + 4^3 + 5^3 | |
// 1 + 8 + 27 + 64 + 125 = 225 | |
cubeSum(2,3) | |
// 3^3 |
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