Find the next perfect square

Find the next perfect square

// 12/22/2015
// You might know some pretty large perfect squares. But what about the NEXT one?

// Complete the findNextSquare method that finds the next integral perfect square after the one passed as a parameter. Recall that 
an integral perfect square is an integer n such that sqrt(n) is also an integer.

// If the parameter is itself not a perfect square, than -1 should be returned. You may assume the parameter is positive.
// Examples:
// findNextSquare(121) --> returns 144
// findNextSquare(625) --> returns 676
// findNextSquare(114) --> returns -1 since 114 is not a perfect

// My Solution:

function findNextSquare(sq){
    var root1;
    var nextroot;
    if(Math.sqrt(sq)%1 ===0){
         root1=Math.sqrt(sq)
         nextroot=root1+1
    }else{
        return -1;
    }
    return nextroot*nextroot;
}

findNextSquare(625) 


// Or using ternary operator

function findNextSquare(sq){
    return Math.sqrt(sq)%1===0 ? Math.pow(Math.sqrt(sq)+1,2) : -1
}

Using ES6 Arrow functions and ternary operator:
let findNextSquare = (sq) => Math.sqrt(sq)%1===0 ? Math.pow(Math.sqrt(sq)+1,2) : -1

function findNextSquare(sq) {
// Check if the square root is an integer
const sqrt = Math.sqrt(sq);
if (Number.isInteger(sqrt)) {
// Find the next perfect square
const nextSquare = Math.pow(sqrt + 1, 2);
return nextSquare;
} else {
// If the parameter is not a perfect square, return -1
return -1;
}
}

// Example usage:
console.log(findNextSquare(9)); // Output: 16 (next perfect square after 9)
console.log(findNextSquare(25)); // Output: 36 (next perfect square after 25)
console.log(findNextSquare(10)); // Output: -1 (10 is not a perfect square)