Created
October 3, 2013 16:48
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#!/usr/bin/env python | |
# -*- coding: utf-8 -*- | |
""" | |
Combinatorial Optimization - B.Korte, J.Vygen | |
Algorithm 1.1 | |
Path Enumeration Algorithm | |
""" | |
def back_track(n): | |
"""Generate all permutations of 0 .. n-1""" | |
# step 1: initialize | |
p = range(n) | |
yield p | |
i = n - 2 | |
while i >= 0: | |
# step 2: find 'k' | |
aux = [False] * n | |
for j in range(i): | |
aux[p[j]] = True | |
k = p[i] + 1 | |
while k < n and aux[k]: | |
k += 1 | |
# step 3 | |
if k < n: | |
p[i] = k | |
if i == n - 1: | |
yield p | |
if i < n - 1: | |
p[i + 1] = -1 | |
i += 1 | |
if k == n: | |
i -= 1 | |
def minimum_path(points): | |
def distance(p, q): | |
return max(abs(p[0] - q[0]), abs(p[1] - q[1])) | |
ret = None | |
n = len(points) | |
for p in back_track(n): | |
x = sum(distance(points[p[i]], points[p[i + 1]]) for i in range(n - 1)) | |
if not ret or x < ret[0]: | |
ret = (x, [points[i] for i in p]) | |
return ret | |
if __name__ == '__main__': | |
import itertools | |
for x in back_track(4): | |
print x | |
print len(list(back_track(5))) | |
# Using built-in function. | |
for x in itertools.permutations(range(4)): | |
print x | |
print minimum_path([(1, 1), (5, 2), (1, 4), (3, 3), (4, 8), (2, 10)]) |
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