Created
October 25, 2011 21:20
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Transitive closure solution in Matlab
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function A=transclose(A) | |
%returns the transitive closure matrix of the input matrix | |
%input: A(i,j) is 1 if the binary relation if (element i) R (element j) using the %notation in the introduction | |
%of http://en.wikipedia.org/wiki/Transitive_closure | |
% | |
%Usage example: Implements the first example problem on https://www.4clojure.com/problem/84 | |
% | |
%divideskey=[2 3 4 8 9 27]; | |
%%I don't actually use that variable, but it keeps track of what my matrix means | |
% | |
%divides=zeros(6) | |
% | |
%divides(4,3)=1 %Add [8,4] to the relation | |
%divides(5,2)=1 %Add [9 3] to the relation | |
%divides(3,1)=1 %Add [4 2] to the relation | |
%divides(6,5)=1 %Add [27 9] to the relation | |
% | |
%transdiv=transclose(divides); | |
%%this returns the matrix | |
% transdiv=[ | |
% 0 0 0 0 0 0 | |
% 0 0 0 0 0 0 | |
% 1 0 0 0 0 0 | |
% 1 0 1 0 0 0 | |
% 0 1 0 0 0 0 | |
% 0 1 0 0 1 0]; | |
for i = 1:size(A,1) | |
for j = 1:size(A,2) | |
t=(A(i,j)==1 & A(j,:)==1); | |
A(i,t)=1; | |
end | |
end |
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