Created
November 28, 2012 08:46
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SICP q2.41
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| ; 1 <= k < j < i <= n | |
| ; | |
| ; e.g.) | |
| ; s = 6 | |
| ; 1 + 2 + 3 = 6 | |
| ; | |
| ; s = 7 | |
| ; 1 + 2 + 4 = 7 | |
| ; | |
| ; s = 8 | |
| ; 1 + 2 + 5 = 8 | |
| ; 1 + 3 + 4 = 8 | |
| ; | |
| ; s = 9 | |
| ; 1 + 2 + 6 = 9 | |
| ; 1 + 3 + 5 = 9 | |
| ; | |
| ; s = 10 | |
| ; 1 + 2 + 7 = 10 | |
| ; 1 + 3 + 6 = 10 | |
| ; 1 + 4 + 5 = 10 | |
| ; 2 + 3 + 5 = 10 | |
| ; | |
| ; 方針 | |
| ; まず、 | |
| ; 1 <= k < j < i <= n | |
| ; なる(i j k)の並びの一覧を全て作り、 | |
| ; そのあと和がsになるような並びだけになるようにfilterすれば良さそう | |
| ; | |
| ; 最終的な呼び出し方は | |
| ; (define n 10) | |
| ; (define s 6) | |
| ; (make-s n s) | |
| ; みたいな感じでいいのかな | |
| ; 必要となりそうなdefineをとりあえず書いておく | |
| ; nil | |
| (define nil '()) | |
| ; 1ずつ増えるような数列 | |
| (define (enumerate-interval low high) | |
| (if (> low high) | |
| nil | |
| (cons low (enumerate-interval (+ low 1) high)))) | |
| ; listを作るaccumulate | |
| (define (accumulate op initial sequence) | |
| (if (null? sequence) | |
| initial | |
| (op (car sequence) | |
| (accumulate op initial (cdr sequence))))) | |
| ; まず、 | |
| ; 1 <= k < j < i <= n | |
| ; なる(i j k)の並びの一覧を全て作るので、 | |
| ; p.71のaccumulateを参考に(list i j k)となるようにする | |
| ; | |
| ; (1 2 3 4 5) | |
| ; | (enumerate-interval 1 (- i 1)) のmapでlist内listができたから | |
| ; (() (2 1) ((3 1) (3 2)) ((4 1) (4 2) (4 3)) ((5 1) (5 2) (5 3) (5 4))) | |
| ; | (enumerate-interval 1 (- j 1)) のmapでさらにlist内listができる | |
| ; (() (()) (() ((3 2 1))) (() ((4 2 1)) ((4 3 1) (4 3 2))) (() ((5 2 1)) ((5 3 1) (5 3 2)) ((5 4 1) (5 4 2) (5 4 3)))) | |
| ; あとはこれをflatにすればいい | |
| ; | |
| ; まず、3つの並びにするのは | |
| ; | |
| ; (map (lambda (i) | |
| ; (map (lambda (j) | |
| ; (map (lambda (k) (list i j k)) | |
| ; (enumerate-interval 1 (- j 1)))) | |
| ; (enumerate-interval 1 (- i 1)))) | |
| ; (enumerate-interval 1 n)) | |
| ; | |
| ; これをflatにしたいのでp.71の | |
| (define (flatmap proc seq) | |
| (accumulate append nil (map proc seq))) | |
| ; を使ってmapをflatmapに変える | |
| ; | |
| ; (flatmap (lambda (i) | |
| ; (flatmap (lambda (j) | |
| ; (map (lambda (k) (list i j k)) | |
| ; (enumerate-interval 1 (- j 1)))) | |
| ; (enumerate-interval 1 (- i 1)))) | |
| ; (enumerate-interval 1 n)) | |
| ; 次にfilterを作る | |
| ; (define s 6) | |
| ; (s-sum? (list 1 2 3) s) | |
| ; みたいなのがあれば良さそう | |
| ; | |
| ; listの数の足し算はaccumulate使ってcount-leavesを思い出してsum-leavesを作ればいいかな | |
| (define (sum-leaves t) (accumulate + 0 t)) | |
| ; そうするとs-sum?はsとsum-leavesの比較なので | |
| (define (s-sum? seq s) (= s (sum-leaves seq))) | |
| ; ただ、make-sの外でs-sum?をdefineするとsが外に出るのが何となく嫌なのでlambdaでいいかも | |
| ; ということで、あとはこれらをまとめて | |
| (define (make-s n s) | |
| (filter (lambda (seq) (= s (sum-leaves seq))) | |
| (flatmap (lambda (i) | |
| (flatmap (lambda (j) | |
| (map (lambda (k) (list i j k)) | |
| (enumerate-interval 1 (- j 1)))) | |
| (enumerate-interval 1 (- i 1)))) | |
| (enumerate-interval 1 n)))) | |
| (define n 10) | |
| (print (make-s n 6)) ; ((3 2 1)) | |
| (print (make-s n 8)) ; ((4 3 1) (5 2 1)) |
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