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Kenyan phone number regular expression
@LukeNgirubiu
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LukeNgirubiu commented Nov 23, 2023

The python code snippet below validates a kenyan mobile phone number (For all service providers). The following 8 formats are valid. Any other format is invalid.

  1. 07XXXXXXXX
  2. 2547XXXXXXXX
  3. 7XXXXXXXX
  4. +2547XXXXXXXX
  5. 01XXXXXXXX
  6. 1XXXXXXXX
  7. +2541XXXXXXXX
  8. 2541XXXXXXXX
    validating_kenyan_number
    If the value of valid is None, then the mobile number provided doesn't match any of the formats listed above.

@Steven-zion
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right now we have number starting with both 07 and 01, what's the regex for that?

@LukeNgirubiu
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LukeNgirubiu commented Apr 19, 2024 via email

@Code-Buddie
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`import re

pattern = r'^(+254|0)([7][0-9]|[1][0-1]){1}[0-9]{1}[0-9]{6}$'

Test the pattern

phone_numbers = [
"+254712345678",
"0712345678",
"0112345678"
]

for number in phone_numbers:
if re.match(pattern, number):
print(f"{number} is a valid phone number.")
else:
print(f"{number} is not a valid phone number.")
`

@Steven-zion
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the phone input am using holds the phone to state in the format +254 712 345678, it has refused to pass most regex. can it be the spacing. please provide me with a regex that validates this exactly as it is, thanks

@LukeNgirubiu
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LukeNgirubiu commented May 4, 2024 via email

@ElzaCremin
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ElzaCremin commented May 15, 2024

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@obbyK
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obbyK commented Jun 14, 2024

Works with Java, but you can probably simplify them further.

Safaricom (\\+?254|0)?([7][0129][0-9]|[7][4][0123568]|[7][5][789]|[7][6][89]|[1][1][012345]){1}[0-9]{6}
Airtel (\\+?254|0)?([7][38][0-9]|[7][5][0123456]|[7][6][2]|[1][0][012345678]){1}[0-9]{6}
Telkom (\\+?254|0)?(77[0-9]){1}[0-9]{6}
Faiba (\\+?254|0)?(747){1}[0-9]{6}
Equitel (\\+?254|0)?(76[3456]){1}[0-9]{6}

@Bradleykingz
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(+?2547\d{8}|07\d{8}|+?25411\d{7}|011\d{7})

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