Created
September 3, 2019 05:58
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Alternating characters
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// Time complexity: O(n) where n is the number of characters. | |
// Space complexity: O(1) for a few variables. | |
function alternatingCharacters(x) { | |
const len = x.length; | |
if (len < 2) return 0; | |
let lastChar = x[0]; | |
let count = 0; | |
let countA = lastChar === 'a' ? 1 : 0; | |
let countB = lastChar === 'b' ? 1 : 0; | |
for (let i = 1; i < len; i += 1) { | |
const n = x[i]; | |
// If current letter is the same as the last seen letter, | |
// increment `count`. | |
if (lastChar === n) count += 1; | |
if ('a' === n) countA += 1; | |
if ('b' === n) countB += 1; | |
lastChar = n; | |
} | |
// Here compare for cases where `count` is 0 as all letters | |
// are alternating but the number of A and the number of B | |
// are not the same. | |
return count === 0 ? | |
Math.abs(countA - countB) : | |
count; | |
} | |
function main() { | |
const a = [ | |
'aaaa', | |
'bbbbb', | |
'abababab', | |
'bababa', | |
'aaabbb', | |
'aaaab', | |
'bbbbba', | |
'ababababa', | |
'bababab', | |
]; | |
a.forEach((n) => { | |
console.log('Alternating characters: ', n, alternatingCharacters(n)); | |
}); | |
} | |
console.clear(); | |
main(); |
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