script to clean up files in the bazel cache

clean-bazel-cache.sh

#! /bin/bash -e
#
# clean up everything in CACHE_DIR last accessed more than DAYS days ago.
# also removes files with bogus timestamps in the future.
#
# -----------------------------------------------------------------------
# Copyright 2021 Todd Derr ([email protected])
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
#     http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.

readonly CACHE_DIR="${1-${HOME}/.cache/bazel}"
readonly DAYS="${2-30}"
readonly dirlist="$(tempfile)"

# something is dropping non-writable directories in the cache
find "${CACHE_DIR}" -type d -a \! -writable -fprint0 ${dirlist}
if [[ -s ${dirlist} ]]; then
  echo "Fixing $(tr -cd '\0' < ${dirlist} | wc -c) non-writeable directories"
  xargs -0 -a "${dirlist}" chmod +w
fi

echo "Cleaning files in ${CACHE_DIR} with atime >${DAYS} days"
find "${CACHE_DIR}" \( -type f -o -type l \) -a \
  \( -atime "+${DAYS}" -o -newermt "1 day" \) -print0 |
  xargs -r -0 rm
echo -n "Cleaning empty directories..."
while true; do
  # never remove CACHE_DIR itself
  find "${CACHE_DIR}" -type d \! -path "${CACHE_DIR}" -empty -fprint0 ${dirlist}
  if [[ -s ${dirlist} ]]; then
     echo -n '.'
     xargs -0 -a "${dirlist}" rmdir
   else
     break;
  fi
done
echo " done."
rm "${dirlist}"

The shebang should be something like #!/bin/bash. Otherwise you may get an error like ./clean-bazel-cache.sh: 12: [[: not found.

good catch, thanks! fixed.