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#!/usr/bin/env python | |
# -*- coding: utf-8 -*- | |
import Queue | |
import argparse | |
import os | |
import random | |
import subprocess | |
import sys | |
import threading | |
import time |
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n, m = map(int, raw_input().split()) | |
table = [map(int, list(raw_input())) for _ in xrange(n)] | |
weighted_table = [] | |
for r in table: | |
if sum(r) == 0: | |
print -1 | |
exit() | |
weighted_row = [] | |
for i in xrange(len(r)): | |
if r[i] == 1: |
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#include <stdio.h> | |
#include <string.h> | |
void reverse_char_array(char * first, char * last) { | |
while (first != last && first != --last) { | |
*first ^= *last; | |
*last ^= *first; | |
*first++ ^= *last; | |
} | |
} | |
void reverse_string(char * sentence) { |
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#include <stdio.h> | |
#include <stdlib.h> | |
#include <string.h> | |
#include <sys/time.h> | |
#include <pthread.h> | |
#include <assert.h> | |
#define CANDSIZE 1024 | |
// #define BUFSIZE 8 * 1024 * 1024 |
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#include <stdio.h> | |
#include <stdlib.h> | |
#include <string.h> | |
#include <stdint.h> | |
#include <unistd.h> | |
#include <assert.h> | |
#include <sys/time.h> | |
#include <pthread.h> |
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#include <stdio.h> | |
#include <stdlib.h> | |
#include <string.h> | |
#include <unistd.h> | |
#include <sys/time.h> | |
#define BUF_SIZE (1<<16) | |
#define LIST_LEN (1024*1024*38) | |
#define WORD_LEN (16) |
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//Dog.java | |
public class Dog extends Animal { | |
public final String mMyString = "bark"; | |
@Override | |
public void doSomething() { | |
System.out.print(mMyString); | |
} | |
} |
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#include <stdio.h> | |
#include <stdlib.h> | |
#include <sys/file.h> | |
#include <unistd.h> | |
int main() { | |
FILE * f1 = fopen("output1.txt", "a"); | |
FILE * f2 = fopen("output2.txt", "a"); | |
char buf[4] = {0}; |
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#!/usr/bin/env python3 | |
# -*- coding: utf-8 -*- | |
''' | |
請用少於 50 (UPD: 45) 個字元的 Python Code 將字串 s 每四個字元為一組反序呈現( s 的長度是 4 的倍數), 舉例 當 s="abcd1234efgh5678" | |
目前允許多行程式碼: 換行算一個字元, 一層縮排算一個字元 | |
''' | |
s = 'EFGHABCD56781234' |
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n = int(input()) | |
t = [0] * (n + 1) | |
def find_min_test(x, t): | |
if x < 3: | |
t[x] = x | |
return x | |
if t[x]: | |
return t[x] | |
t[x] = min(max(i, 1 + find_min_test(x - i, t)) for i in range(1, x + 1)) |
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