Go snippet: make http requests concurrently but timeout after a specified interval

http_timeout.go

package main

import "log"
import "net/http"
import "time"

type Response struct {
	StatusCode int
	Url        string
}

func fetch(url string, done chan *Response, quit chan bool) {
	resp, err := http.Get(url)
	if err != nil {
		log.Fatal(err)
	}
	for {
		select {
		case done <- &Response{resp.StatusCode, url}:
			return
		case <-quit:
			return
		}
	}
}

func waitForAll(done chan *Response, quit chan bool, duration time.Duration) []*Response {
	responses := []*Response{}
	timeout := time.After(duration)

	for {
		select {
		case resp := <-done:
			responses = append(responses, resp)
		case <-timeout:
			close(quit)
			return responses
		}
	}
}

func main() {
	urls := []string{"http://flinc.org", "http://google.de", "http://amazon.de"}
	quit := make(chan bool)
	done := make(chan *Response, 0)

	log.Printf("Fetching %d URLs concurrently", len(urls))
	for _, url := range urls {
		go fetch(url, done, quit)
	}

	responses := waitForAll(done, quit, 1000*time.Millisecond)
	log.Printf("%d responded in the timeframe", len(responses))
	for _, resp := range responses {
		log.Printf("%d %s", resp.StatusCode, resp.Url)
	}
}

Introduced a quit channel, which should stop the goroutine leaking.