Created
September 30, 2020 10:24
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One sided test for hypothesis about proportion
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#= | |
Newborn babies are more likely to be boys than girls. | |
A random sample found 13 173 boys were born among 25 468 | |
newborn children. Population: All children born that time period. Alternatively, | |
the unknown p could be the unknown probability. | |
=# | |
b = 13173 | |
n = 25486 | |
p̂ = b/n | |
#H0 p = 0.5 | |
p0 = 0.5 #null value | |
# Check if n is large enough | |
n*p0 > 5 | |
n*(1 - p0) | |
# Every below computed under H0 | |
SE = sqrt(p0*(1-p0)/n) | |
# Compute the test statistic | |
z = (p̂ - p0)/SE | |
# z is large, evidence in favour of H1: p > 0.5 | |
α = 0.05 | |
z0 = quantile(Normal(0,1), 1 - α) | |
if z > z0 | |
println("Reject the null! With 0.05 significance ... p>0.5") | |
else | |
println("Null hypothesis cannot be rejected") | |
end |
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