SegueHandlerType for Swift 3

SegueHandlerType.swift

/* The SegueHandlerType pattern, as seen on [1, 2], adapted for the changed Swift 3 syntax.

 [1] https://developer.apple.com/library/content/samplecode/Lister/Listings/Lister_SegueHandlerType_swift.html
 [2] https://www.natashatherobot.com/protocol-oriented-segue-identifiers-swift/
 */

protocol SegueHandlerType {

    // `typealias` has been changed to `associatedtype` for Protocols in Swift 3.
    associatedtype SegueIdentifier: RawRepresentable
}

extension SegueHandlerType where Self: UIViewController, SegueIdentifier.RawValue == String {

    // This used to be `performSegueWithIdentifier(...)`.
    func performSegue(withIdentifier identifier: SegueIdentifier, sender: Any?) {
        performSegue(withIdentifier: identifier.rawValue, sender: sender)
    }

    func segueIdentifier(for segue: UIStoryboardSegue) -> SegueIdentifier {
        guard let identifier = segue.identifier, let segueIdentifier = SegueIdentifier(rawValue: identifier) else {
            fatalError("Couldn't handle segue identifier \(String(describing: segue.identifier)) for view controller of type \(type(of: self)).")
        }

        return segueIdentifier
    }
}

import UIKit

class ViewController: UIViewController {

    override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
        switch segueIdentifier(for: segue) {
        case .showFoo:
            // prepare for segue to Foo
            break
        case .showBar:
            // prepare for segue to Bar
            break
        }
    }

}

/* We're using a protocol extension here to separate UIViewController concerns.
 See [1, 2] for more info on this.

 [1] https://developer.apple.com/library/content/documentation/Swift/Conceptual/Swift_Programming_Language/Protocols.html#//apple_ref/doc/uid/TP40014097-CH25-ID521
 [2] https://www.natashatherobot.com/using-swift-extensions/
 */

extension ViewController: SegueHandlerType {

    enum SegueIdentifier: String {
        case showFoo
        case showBar
    }
}

Hi, thanks for the gist !

the switch statement would be swiftier without the break statements

class ViewController: UIViewController {

    override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
        switch segueIdentifier(for: segue) {
        case .showFoo:
            // prepare for segue to Foo
        case .showBar:
            // prepare for segue to Bar
        }
    }

}