Created
October 9, 2012 03:16
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Calculate how many permutations there are for the Android pattern lock-screen
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NODES = { | |
1 => [2,4,5], | |
2 => [1,3,4,5,6], | |
3 => [2,5,6], | |
4 => [1,2,5,7,8], | |
5 => [1,2,3,4,6,7,8,9], | |
6 => [2,3,5,8,9], | |
7 => [4,5,8], | |
8 => [4,5,6,7,9], | |
9 => [5,6,8] | |
} | |
STEPS = 3 | |
def path_next(paths) | |
new_paths = [] | |
paths.each do |p| | |
available_next_steps = NODES[p.last] - p | |
available_next_steps.each do |s| | |
new_steps = p + [s] | |
new_paths << new_steps | |
end | |
end | |
new_paths | |
end | |
paths = [] | |
NODES.each do |k,v| | |
path = [[k]] | |
STEPS.times do | |
path = path_next(path) | |
end | |
paths = paths + path.reject{|a|a.size != 4} | |
end | |
puts paths.size # 496 |
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