Print xml node names in basic XPath format.

print-xml-tree-nodes.groovy

class NodePrinter{

	private String filePath
	private String namespacePrefix

	NodePrinter(String filePath, String namespacePrefix){
		this.filePath = filePath
		this.namespacePrefix = namespacePrefix
	}

	def printTree(){
		def rootNode = new XmlParser().parse(new File(this.filePath))
		this.printNode(rootNode, "/")
	}

	def skipNode(def node){
		node.children().size() > 1
	}

	def printNode(def node, String path){
		String fullPath = "${path}/${node.name()}".replace(namespacePrefix, "")
		if(!skipNode(node)){
			println fullPath
		}
		node.children().each {
			if(it instanceof groovy.util.Node){
				printNode(it, fullPath)	
			} else if(it instanceof java.lang.String) {
				// Ignore text node
			} else {
				println "Unknown node: " + it.getClass()
			}
		}
	}	
}

// Run
def path = "xml-file-path.xml"
new NodePrinter(path, "ns:").printTree()