Use XPath 2.0 syntax to list all the nodes in an XML file

ListXMLNodes

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:template match="text()"/>
    <xsl:template match="*|@*">
            <xsl:value-of select="
            string-join(
			   distinct-values(
				  (//*|//@*)
					 /string-join(
						(ancestor::node()/name(),
						 if (self::attribute())
							then concat('@',name())
							else name()),
						'/')),
			   '&#xA;')"/>
			
    </xsl:template>
</xsl:stylesheet>
<!-- source: http://stackoverflow.com/questions/4051987/list-every-node-in-an-xml-file -->