mycodeschool/BalancedParentheses.cpp

Yashaggarwal35 · 2018-09-08T11:27:52Z

//TRY THIS OUT

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int top = -1;
char s[100];

void balanced_parentheses(){
int i,l;
char exp[100],x,y;
printf("Enter the exp: \n");
scanf("%s",exp);
l = strlen(exp);
for(i = 0;i<l;i++){
if(exp[i]=='(' || exp[i]=='{' || exp[i]=='['){
x = exp[i];
push(exp[i]);
}
else if(exp[i]==')' || exp[i]=='}' || exp[i]==']'){
y = exp[i];
pop(y);
}
}
}

void push(char x){
top++;
s[top] = x;
}

void pop(char y){
if(y==')'){
if(s[top]=='('){
top=top-1;
}
}
else if(y=='}'){
if(s[top]=='{'){
top = top-1;
}
}
else if(y==']'){
if(s[top]=='['){
top = top-1;
}
}
else{
return "\0";
}
}

void Print(){
int i;
if(top==-1){
printf("\nThey are balanced parentheses");
}
else{
printf("\nFALSE! not balanced ones..because\n");

    for(i=0;i<=top;i++){
        if(s[top]=='('){
                printf("You should end with: ')' ");
           }
        else if(s[top]=='{'){
            printf("You should end with: '}' ");
        }
        else if(s[top]=='['){
            printf("You should end with: ']'");
        }
        else{
            printf("INVALID expression here!");
        }
        return;
    }

}

}

int main(){
balanced_parentheses();
Print();
}

suresh68 · 2018-10-19T11:20:49Z

// try this out

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<stdbool.h>
struct node
{
char data;
struct node* next;
};
struct node* top = NULL;
void push(char x)
{
struct node* temp = (struct node*)malloc(sizeof(struct node));
temp->data = x;
temp->next = top;
top = temp;
}
void pop()
{
struct node* temp = top;
if(top == NULL)
{
return;
}
temp = top;
top = top->next;
free(temp);
}
bool arepair(char opening,char closing)
{
if(opening == '(' && closing == ')') return true;
else if(opening == '{' && closing == '}') return true;
else if(opening == '[' && closing == ']') return true;
else return false;
}
bool checkbalancepar(char arr,int length)
{
int i;
for(i=0;i<length;i++)
{
if((arr+i)=='{'||(arr+i)=='['||(arr+i)=='(')
{
push((arr+i));
}
else if((arr+i)=='}'||(arr+i)==']'||(arr+i)==')')
{
if(top==NULL||!arepair(top->data,(arr+i)))
{
printf("paranthesis doesn't match\n");
return false;
}
else
{
pop();
}
}
}
return (top==NULL)? true:false;
}
void print(struct node top)
{
struct node* temp = top;
if(top == NULL)
{
printf("the stack is empty\n");
return;
}
while(temp!= NULL)
{
printf("%c ",temp->data);
temp = temp->next;
}
printf("\n");
}
int main()
{
char *arr;
int num,i;
printf("ener the no paranthesis elements: ");
scanf("%d",&num);
arr = (char ) calloc(num,sizeof(char));
printf("enter the string: ");
for(i=0;i<num;i++)
{
scanf("%c ",(arr+i));
}
for(i=0;i<num;i++)
{
printf("%c ",(arr+i));
}
if(checkbalancepar(arr,num))
{
printf("balanced parenthesis\n");
}
else
printf("unbalanced paranthesis\n");
print(top);
return 0;
}

suresh68 · 2018-10-19T11:25:32Z

@

Hello guys.. I have implemented the same in C using stack. The following is my code. It's having no issues as far as pushing data is concerned, however, it doesn't seem to pop the data.. Please help me out debug this code

// Stacks: Check for balanced paranthesis

include<stdio.h>

include<stdlib.h>

define MAX_SIZE 100

char c[MAX_SIZE] ;
struct Node {
char data;
struct Node * next;
};
struct Node * top = NULL ;
void Push(int data){
struct Node * temp = (struct Node *)malloc(sizeof(struct Node));
temp->data = data;
temp->next = top ;
top = temp ;
}

void Pop(){
if(top == NULL){
printf("There are no items in the stack to pop\n");
return;
}
struct Node * temp = top;
top = top->next ;
free(temp);
}

void Print(){
if(top == NULL){
printf("Stack is empty\n");
}
struct Node * temp = top ;
printf("\nThe current stack is: ");
while(temp != NULL){
printf(" %c",temp->data);
temp = temp->next ;
}
printf("\n");
}

void CheckforBalancedparanthesis(char c[], int length){
//now as we scan the expression push the character into the stack
int i;
for(i=0;i<length;i++){
if((c[i] == '(' ) || (c[i] == '{' ) || (c[i] == '[' ))
{
Push(c[i]);
}
else if((c[i] == ')' ) || (c[i] == '}' ) || (c[i] == ']' ))
{
if((top == NULL) || (c[i] != top->data))
{
printf("Paranthesis don't match \n");
return ;
}
else{
Pop();
}
}
printf(" %c",top->data);
}
return (top == NULL)?("Paranthesis match"):("Parenthesis don't match") ;
}
int main(){
int length;
printf("Enter a string of paranthesis: ");
scanf("%s",c);
//printf("%s",c);
length = strlen(c);
CheckforBalancedparanthesis(c,length);
Print(top);
//Pop();Print(top);Pop();Print(top);
//Push(3);Push(4);Push(1);Push(7);Print(top);Pop();Print(top);Pop();Print(top);
}

sir u haven't compared the previous paranthesis with the current paranthesis entered that why it is throwing the error while popping
//Try this out
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<stdbool.h>
struct node
{
char data;
struct node* next;
};
struct node* top = NULL;
void push(char x)
{
struct node* temp = (struct node*)malloc(sizeof(struct node));
temp->data = x;
temp->next = top;
top = temp;
}
void pop()
{
struct node* temp = top;
if(top == NULL)
{
return;
}
temp = top;
top = top->next;
free(temp);
}
bool arepair(char opening,char closing)
{
if(opening == '(' && closing == ')') return true;
else if(opening == '{' && closing == '}') return true;
else if(opening == '[' && closing == ']') return true;
else return false;
}
bool checkbalancepar(char arr,int length)
{
int i;
for(i=0;i<length;i++)
{
if((arr+i)=='{'||(arr+i)=='['||(arr+i)=='(')
{
push((arr+i));
}
else if((arr+i)=='}'||(arr+i)==']'||(arr+i)==')')
{
if(top==NULL||!arepair(top->data,(arr+i)))
{
printf("paranthesis doesn't match\n");
return false;
}
else
{
pop();
}
}
}
return (top==NULL)? true:false;
}
void print(struct node top)
{
struct node* temp = top;
if(top == NULL)
{
printf("the stack is empty\n");
return;
}
while(temp!= NULL)
{
printf("%c ",temp->data);
temp = temp->next;
}
printf("\n");
}
int main()
{
char *arr;
int num,i;
printf("ener the no paranthesis elements: ");
scanf("%d",&num);
arr = (char ) calloc(num,sizeof(char));
printf("enter the string: ");
for(i=0;i<num;i++)
{
scanf("%c ",(arr+i));
}
for(i=0;i<num;i++)
{
printf("%c ",(arr+i));
}
if(checkbalancepar(arr,num))
{
printf("balanced parenthesis\n");
}
else
printf("unbalanced paranthesis\n");
print(top);
return 0;
}

ALisaeed909 · 2018-10-26T14:41:33Z

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX 100

char stack_A[MAX];
int c;
int top =-1;

char push(char c){
if(top==MAX-1){
printf("Erorr is overflow\n");
}
top ++;
stack_A[top] = c;
return c;
}
char pop(){
if(top==-1){
printf("Error of lowerflow\n");
}
top--;
}

int main(){
char exp[MAX];
printf("Enter the thing\n");
scanf("%s",exp);
int i;
for(i=0;i<strlen(exp);i++){
if(exp[i]=='('||exp[i]=='{'||exp[i]=='['){
push(exp[i]);
}
else if (exp[i]==')'||exp[i]=='}'||exp[i]=="]"){
if (top == -1 || exp[i] != c){

        }
    }    else{
             pop();
     }
}

if (top == -1){
    printf("True\n");
} else{
    printf("False\n");
}

}

komal14prasad · 2018-11-29T23:07:01Z

Can you share the code in Java, I tried implementing the same logic in java but unable to develope one

jazimabbas · 2019-02-18T22:57:22Z

Please anyone give me examples of data structures. Because practise makes a man perfect so plz help me out. Thanks in advance

Rohith-Rajan · 2019-06-16T06:08:27Z

This is my version of the code

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <string>
#include <stack>

using namespace std;

char openingBracket(char closing_bracket)
{
    char opening_bracket;
    if (closing_bracket == '}') 
      return '{' ;
    else if (closing_bracket == ')') 
     return '(' ;
    else if (closing_bracket == ']') 
     return '[' ;
}
void areParenthesisBalanced(string name)
{
    stack<char> S;
    bool isBalanced = true;
    for(int i=0;i<name.length();i++)
    {
        if( name[i] == '(' || name[i] == '{' || name[i] == '[' )
        {
        S.push(name[i]);
        }
        else if(name[i] == '}' || name[i] == ')' || name[i] == ']')
        {
            if( (S.empty() && i!=name.length()) || (S.top()!= openingBracket(name[i]) ))
            {
               isBalanced = false;
               break;
            }
            else
            {
               S.pop();
            }
        }
    }
    if(isBalanced)
    {
        cout<<"\n The expression is balanced!!\n";
    }
    else if(!isBalanced)
    {
       cout << "The expression is not balanced!\n";
    }
    
}
int main()
{
    string name ;
    cout<<"Enter an expression:";
    getline(cin,name);
    areParenthesisBalanced(name);

    return 0;
}

nimalatifi · 2019-07-10T12:34:25Z

hi guys.
i think you missed one important issue.

Did you ever attempt to inserting closing bracket before opening?!!

senthilnathan87 · 2019-08-26T18:35:22Z

Can you share the code in Java, I tried implementing the same logic in java but unable to develope one

import org.testng.Assert;
import org.testng.annotations.Test;
import java.util.Stack;
/**
 * ExpressionEvaluator
 */
public class ExpressionEvaluator {

    @Test
    public void expressionsTest() {
        Assert.assertTrue(BalancedExpressionAlg.isBalanced("{A+B}"));
        Assert.assertTrue(BalancedExpressionAlg.isBalanced("{ (C*9) * [10] - (A+B) }"));
        Assert.assertFalse(BalancedExpressionAlg.isBalanced("{ { () }"));
        Assert.assertTrue(BalancedExpressionAlg.isBalanced("{ as } (C*2)"));
        Assert.assertFalse(BalancedExpressionAlg.isBalanced("}{"));
    }
    
}

class BalancedExpressionAlg {

    // Works in O(n)
    static boolean isBalanced(String expr) {
        Stack<Character> stack = new Stack<>();
        char[] chars = expr.toCharArray();
        for(char ch : chars) {
            if(ch == '{' || ch == '[' || ch == '(') {
                stack.push(ch);
            }
            switch(ch) {
                case '}':
                    if(stack.isEmpty() || stack.pop() != '{') return false;
                break;
                case ']':
                    if(stack.isEmpty() || stack.pop() != '[') return false;
                break;
                case ')':
                    if(stack.isEmpty() || stack.pop() != '(') return false;
                break;                                 
            }

        }
        if(stack.isEmpty()) {
            return true;
        }
        return false;
    }
}

misterpoloy · 2020-01-10T19:24:11Z

This was my solution:

#include <iostream>
#include <stack>
#include <string>

bool testBalance(std::string str) {
    std::stack<char> expressions;
    for (int i = 0; i < str.size(); i++) {
        char current = str[i];
        if (current == '{' || current == '[' || current == '(') {
            expressions.push(current);
            continue;
        }
        if (current == '}' || current == ']' || current == ')') {
            if (expressions.empty()) {
                return false;
            } else {
             // Compare the match
                char last = expressions.top();
                bool congruent = false;
                switch (last) {
                    case '{':
                        if (current == '}')
                            congruent = true;
                        break;
                    case '[':
                        if (current == ']')
                            congruent = true;
                        break;
                    case '(':
                        if (current == ')')
                            congruent = true;
                        break;
                    default:
                        break;
                }
                if (congruent) {
                    expressions.pop();
                } else {
                    return false;
                }
            }
        }
    }
    return expressions.empty();
};

int main() {
    std::string str;
    getline(std::cin, str);
    std::cout << testBalance(str) << std::endl;
    return 0;
}

asad2200 · 2020-04-21T02:25:46Z

Here the java code ,if someone wants

//------------------------------------

import java.util.Scanner;
import java.util.Stack;

public class CheckParathese {

static boolean checkPair(char opening,char closing){
    if(opening == '(' && closing == ')') return true;
    else if(opening == '{' && closing == '}') return true;
    else if(opening == '[' && closing == ']') return true;
    return false;
}

static boolean isBalanced(String s) {
    char arr[] = s.toCharArray();
    Stack<Character> st = new Stack<Character>();
    for(int i=0;i<s.length();i++){
        if(arr[i] == '(' || arr[i] == '{' || arr[i] == '[')
            st.push(arr[i]);
        else if(arr[i] == ')' || arr[i] == '}' || arr[i] == ']'){
            if(st.empty() || !checkPair(st.peek(),arr[i])){
                return false;
            }else
                st.pop();
        }
    }
    return st.empty()?true:false ;
}

public static void main(String[] args) throws Exception {
    String s;
    Scanner sc = new Scanner(System.in);
    s=sc.nextLine();
    sc.close();
    if(isBalanced(s))
        System.out.print("Paranthases are balanced");
    else
        System.out.print("Paranthases are not balanced");   
}

}
//-------------------------------------

hitsa70 · 2020-04-29T09:48:57Z

import java.util.*;
public class Solution {

public static boolean matchingPeer(char open , char close){
if ( open == '(' && close == ')'){
return true;
}
if ( open == '[' && close == ']'){
return true;
}
if ( open == '{' && close == '}'){
return true;
}
// you can add more open and close rule

else{
return false;
}

}

public static boolean checkBalanced(String equation) 
{
	// Write your code here
	char[] c = equation.toCharArray();
Stack <Character> myStack= new Stack <Character> ();

for (int i = 0; i < c.length; i++)
{
	if(c[i]=='(' || c[i] == '[' || c[i] == '{'){
		myStack.push(c[i]);
        continue;
	}
	else if (c[i]== ')' || c[i]==']' || c[i] == '}'){
        	if(myStack.isEmpty())
                return false;
			if(matchingPeer(myStack.peek(),c[i]) == true){
				myStack.pop();
			
			} else {
				return false;
			}
	}
}
	if(myStack.isEmpty()){
		return true;
	}	
	else {
		return false;
	}
}

}

FredLeg · 2020-05-19T08:26:58Z

JAVASCRIPT

function isParanthesesBalanced( expression ){
  let symbols = {
      'opening': ['(','[','{','«'],
      'closing': [')',']','}','»'],
      'isOpening': function( car ){
        return this.opening.indexOf(car)>=0
      },
      'isClosing': function( car ){
        return this.closing.indexOf(car)>=0
      },
      'isPair': function( opening, closing ){
        let i = this.opening.indexOf(opening)
        if( !(i>=0) ) return false
        return i == this.closing.indexOf(closing)
      }
  }
  let stack = {
    's':       [],
    'push':    function( car ){ this.s.push(car) },
    'pop':     function( car ){ this.s.pop(car) },
    'top':     function(){ return this.s[this.s.length-1] },
    'isEmpty': function(){ return this.s.length==0 }
  }
  for ( let car of expression ) {
    if( symbols.isOpening(car) )
      stack.push(car)
    else if( symbols.isClosing(car) ){
      if( stack.isEmpty() || !symbols.isPair( stack.top(), car ) )
        return false
      else
        stack.pop()
    }
  }
  return stack.isEmpty()
}

let expressions = [
  "[(a+b)*(c+d)]",
  "[()(])",
  "Elle dit « ouh là là » tout le temps.",
  "none",
  ""
]
for( exp of expressions ){
  console.log( exp +" • "+ isParanthesesBalanced(exp) )
}

[(a+b)*(c+d)] • true
[()(]) • false
Elle dit « ouh là là » tout le temps. • true
none • true
 • true

siddharthmagadum16 · 2020-06-09T19:04:10Z

Here's my code. I implemented using stack . The stack is implemented using object oriented implementation using arrays.
`// Stack - ||Object oriented implementation|| using arrays
#include
using namespace std;
#define MAX_SIZE 4

class Stack
{
private:
int A[MAX_SIZE]; // array to store the stack
int top; // variable to mark the top index of stack.
public:
// constructor
Stack()
{
top = -1; // for empty array, set top = -1
}

// Push operation to insert an element on top of stack. 
void Push(int x) 
{
  if(top == MAX_SIZE -1) { // overflow case. 
		printf("Error: stack overflow\n");
		return;
	}
	A[++top] = x;
}

// Pop operation to remove an element from top of stack.
void Pop() 
{
	if(top == -1) { // If stack is empty, pop should throw error. 
		printf("Error: No element to pop\n");
		return;
	}
	top--;
}

// Top operation to return element at top of stack. 
int Top() 
{
	return A[top];
}

// This function will return 1 (true) if stack is empty, 0 (false) otherwise
int IsEmpty()
{
	if(top == -1) return 1;
	return 0;
}

// ONLY FOR TESTING - NOT A VALID OPERATION WITH STACK 
// This function is just to test the implementation of stack. 
// This will print all the elements in the stack at any stage. 
void Print() {
	int i;
	printf("Stack: ");
	for(i = 0;i<=top;i++)
		printf("%d ",A[i]);
	printf("\n");
}

};

int solve(){
Stack S;
char ch=getchar();
while(ch!='\n'){
if(ch=='{' || ch=='(' || ch=='['){
S.Push(ch);
}
else if(ch=='}' || ch==')' || ch==']'){
if(S.IsEmpty() || (S.Top()!='{' && ch=='}') || S.Top()!='(' && ch==')' || S.Top()!='[' && ch==']');
else S.Pop();
}
ch=getchar();
}
S.IsEmpty()?printf("Balanced\n"):printf("Not Balanced\n");
return 0;
}

int main()
{
printf("Enter string of braces:\n");
solve();
return 0;
}`

diegoba90 · 2020-07-12T22:02:46Z

I'm having a hard time with this. How can i make it so that instead of having the user input the string of characters it instead reads it from a file that has lines of different expressions.

rohitverma1999hack · 2020-09-25T06:46:06Z

return S.empty() ? true:false; is kind of redundant (if true return true else return false).
It's not redundant
what if the input is "(".

umamahesh33 · 2020-10-05T18:24:17Z

it will fail for the test case when we include the space in the user input because the taking of string input will not execute after a blank space

shoaibrain · 2020-10-09T14:50:07Z

`def balancedBrackets(string):
#remove all invalid characters. This is optional by the way.If your string only contains [{()}]. You don't have to change input string in any
way
string = [x for x in string if x in '[{()}]]']

stack = []

for char in string:
	if char in '([{':
		stack.append(char)
	else:
		if len(stack) == 0  or not arePair(stack[-1], char):
			return False
		else:
			stack.pop()
if len(stack) == 0:return True
return `False`

def arePair(opening,closing):
if opening == '(' and closing == ')':return True
elif opening == '[' and closing == ']': return True
elif opening == '{' and closing == '}':return True
return False
`

BaseMax · 2021-04-11T16:41:53Z

https://github.com/BaseMax/ValidationParentheses

ibrahimBanat · 2021-06-01T13:25:18Z

Solution Using JavaScript: you can also check the whiteboard and test from here:

class MultiBracketValidation {
  constructor() {
    this.stack = new Stack();
    this.opening = ["{", "(", "[", "<"];
    this.closing = ["}", ")", "]", ">"];
  }
  checkForValidation(input) {
    for (const char of input) {
      if (this.isOpening(char)) {
        this.stack.push(char);
      } else if (this.isClosing(char)) {
        if (
          this.stack.isEmpty() ||
          !this.isPair(this.stack.peek().value, char)
        ) {
          return false;
        } else {
          this.stack.pop();
        }
      }
    }
    return this.stack.isEmpty();
  }
  isOpening(char) {
    return this.opening.indexOf(char) >= 0;
  }
  isClosing(char) {
    return this.closing.indexOf(char) >= 0;
  }
  isPair(opening, closing) {
    return this.closing.indexOf(closing) === this.opening.indexOf(opening);
  }
}

HarshKakran · 2021-07-06T11:49:43Z

Hey, I am a beginner in programming, and tried to implement the pseudo code shared in the video using C++, can you guys share the reviews about the coding style.

bool checkBalancedParenthesis(string exp){
    stack<char> s;
    int n = exp.length();
    for(int i=0; i<n; i++){
        if (exp[i] == '{' || exp[i] == '(' || exp[i] == '['){
            s.push(exp[i]);
        }
        else if(exp[i] == '}' || exp[i] == ')' || exp[i] == ']'){
            if (s.empty())
            return false;
            switch (s.top())
            {
            case '(':
                if (exp[i] == ')')
                    {s.pop();
                    break;}
                else{
                    return false;
                }
            case '{':
                if (exp[i] == '}')
                    {s.pop();
                    break;}
                else{
                    return false;
                }
            case '[':
                if (exp[i] == ']')
                    {s.pop();
                    break;}
                else{
                    return false;
                }
            }
        }    
    }
    return s.empty()?true:false;
}

AshAman999 · 2021-07-23T17:56:44Z

Hey, I am a beginner in programming, and tried to implement the pseudo code shared in the video using C++, can you guys share the reviews about the coding style.

bool checkBalancedParenthesis(string exp){
    stack<char> s;
    int n = exp.length();
    for(int i=0; i<n; i++){
        if (exp[i] == '{' || exp[i] == '(' || exp[i] == '['){
            s.push(exp[i]);
        }
        else if(exp[i] == '}' || exp[i] == ')' || exp[i] == ']'){
            if (s.empty())
            return false;
            switch (s.top())
            {
            case '(':
                if (exp[i] == ')')
                    {s.pop();
                    break;}
                else{
                    return false;
                }
            case '{':
                if (exp[i] == '}')
                    {s.pop();
                    break;}
                else{
                    return false;
                }
            case '[':
                if (exp[i] == ']')
                    {s.pop();
                    break;}
                else{
                    return false;
                }
            }
        }    
    }
    return s.empty()?true:false;
}

If you are waiting for the mentors to reply then they ain't goint to reply and apart from that yeah coding style looks good

	/*
	C++ Program to check for balanced parentheses in an expression using stack.
	Given an expression as string comprising of opening and closing characters
	of parentheses - (), curly braces - {} and square brackets - [], we need to
	check whether symbols are balanced or not.
	*/
	#include<iostream>
	#include<stack>
	#include<string>
	using namespace std;
	// Function to check whether two characters are opening
	// and closing of same type.
	bool ArePair(char opening,char closing)
	{
	if(opening == '(' && closing == ')') return true;
	else if(opening == '{' && closing == '}') return true;
	else if(opening == '[' && closing == ']') return true;
	return false;
	}
	bool AreParanthesesBalanced(string exp)
	{
	stack<char> S;
	for(int i =0;i<exp.length();i++)
	{
	if(exp[i] == '(' \|\| exp[i] == '{' \|\| exp[i] == '[')
	S.push(exp[i]);
	else if(exp[i] == ')' \|\| exp[i] == '}' \|\| exp[i] == ']')
	{
	if(S.empty() \|\| !ArePair(S.top(),exp[i]))
	return false;
	else
	S.pop();
	}
	}
	return S.empty() ? true:false;
	}

	int main()
	{
	/Code to test the function AreParanthesesBalanced/
	string expression;
	cout<<"Enter an expression: "; // input expression from STDIN/Console
	cin>>expression;
	if(AreParanthesesBalanced(expression))
	cout<<"Balanced\n";
	else
	cout<<"Not Balanced\n";
	}

mycodeschool/BalancedParentheses.cpp

Yashaggarwal35 commented Sep 8, 2018

suresh68 commented Oct 19, 2018

suresh68 commented Oct 19, 2018

ALisaeed909 commented Oct 26, 2018

komal14prasad commented Nov 29, 2018

jazimabbas commented Feb 18, 2019

Rohith-Rajan commented Jun 16, 2019

nimalatifi commented Jul 10, 2019

senthilnathan87 commented Aug 26, 2019 •

edited

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misterpoloy commented Jan 10, 2020

asad2200 commented Apr 21, 2020 •

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siddharthmagadum16 commented Jun 9, 2020 •

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rohitverma1999hack commented Sep 25, 2020

umamahesh33 commented Oct 5, 2020

shoaibrain commented Oct 9, 2020 •

edited

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BaseMax commented Apr 11, 2021

ibrahimBanat commented Jun 1, 2021

HarshKakran commented Jul 6, 2021

AshAman999 commented Jul 23, 2021

mycodeschool/BalancedParentheses.cpp

Yashaggarwal35 commented Sep 8, 2018

suresh68 commented Oct 19, 2018

suresh68 commented Oct 19, 2018

include<stdio.h>

include<stdlib.h>

define MAX_SIZE 100

ALisaeed909 commented Oct 26, 2018

komal14prasad commented Nov 29, 2018

jazimabbas commented Feb 18, 2019

Rohith-Rajan commented Jun 16, 2019

nimalatifi commented Jul 10, 2019

senthilnathan87 commented Aug 26, 2019 • edited Loading

misterpoloy commented Jan 10, 2020

asad2200 commented Apr 21, 2020 • edited Loading

hitsa70 commented Apr 29, 2020

FredLeg commented May 19, 2020 • edited Loading

siddharthmagadum16 commented Jun 9, 2020 • edited Loading

diegoba90 commented Jul 12, 2020

rohitverma1999hack commented Sep 25, 2020

umamahesh33 commented Oct 5, 2020

shoaibrain commented Oct 9, 2020 • edited Loading

BaseMax commented Apr 11, 2021

ibrahimBanat commented Jun 1, 2021

HarshKakran commented Jul 6, 2021

AshAman999 commented Jul 23, 2021

senthilnathan87 commented Aug 26, 2019 •

edited

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asad2200 commented Apr 21, 2020 •

edited

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FredLeg commented May 19, 2020 •

edited

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siddharthmagadum16 commented Jun 9, 2020 •

edited

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shoaibrain commented Oct 9, 2020 •

edited

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