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@myuon
Created August 18, 2012 13:03
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SKIコンビネータ2
\abf.fab
= \abf.(I f)(K (ab)f)
= \ab.SI(K(ab))
= \ab.(K(SI)(ab))(K(ab))
= \ab.S(K(SI))K(ab)
= \ab.(K(S(K(SI))K) b)(a b)
= \ab.S(K(S(K(SI))K))ab
= S(K(S(K(SI))K))
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