Given 3 numbers add up their individual digits and return the largest summed one

largestNumberCalc

function largestPhoneCalculator(pn1, pn2, pn3) {
    var aPhoneNumber = [];
    var stringNumber = pn1.toString();
    
    for (var i = 0, lngt = stringNumber.length; i < lngt; i++) {
        aPhoneNumber.push(+stringNumber.charAt(i));
    }
    for (var i = 0, sum = 0; i < aPhoneNumber.length; sum += aPhoneNumber[i++]);
    //console.log(sum);
    
    var aPhoneNumber2 = [];
    var stringNumber2 = pn2.toString();
    
    for (var x = 0, lngt2 = stringNumber2.length; x < lngt2; x++) {
        aPhoneNumber2.push(+stringNumber2.charAt(x));
    }
    for (var x = 0, sum2 = 0; x < aPhoneNumber2.length; sum2 += aPhoneNumber2[x++]);
    //console.log(sum2);
    
    var aPhoneNumber3 = [];
    var stringNumber3 = pn3.toString();
    
    for (var j = 0, lngt3 = stringNumber3.length; j < lngt3; j++) {
        aPhoneNumber3.push(+stringNumber3.charAt(j));
    }
    for (var j = 0, sum3 = 0; j < aPhoneNumber3.length; sum3 += aPhoneNumber3[j++]);
    //console.log(sum3);
    
    if( sum > sum2 && sum > sum3){
        console.log("The largest summed phone number is " + pn1);
    } else if (sum2 > sum && sum2 > sum3){
        console.log("The largest summed phone number is " + pn2);
    }
        else {
            console.log("The largest summed phone number is " + pn3);
        }
    
}  

largestPhoneCalculator(1111111111, 2222222222, 4444444444);