Network overlapping check

Overlap.java

private static boolean overlap(final String net1, final String net2)
{
    SubnetInfo subnet1 = new SubnetUtils(net1).getInfo();
    SubnetInfo subnet2 = new SubnetUtils(net2).getInfo();

    int mask1 = subnet1.asInteger(subnet1.getNetmask());
    int mask2 = subnet2.asInteger(subnet2.getNetmask());

    int maskToUse = mask1 < mask2 ? mask1 : mask2;
    int addr1 = subnet1.asInteger(subnet1.getAddress()) & maskToUse;
    int addr2 = subnet2.asInteger(subnet2.getAddress()) & maskToUse;

    return addr1 == addr2;
}

public static void main(final String[] args)
{
    System.out.println(overlap("192.168.0.0/22", "192.168.0.0/24"));
    System.out.println(overlap("192.168.1.0/22", "192.168.0.0/24"));
    System.out.println(overlap("192.168.2.0/22", "192.168.0.0/24"));
    System.out.println(overlap("192.168.4.0/22", "192.168.0.0/24"));

    System.out.println(overlap("192.168.0.0/24", "192.168.0.0/24"));
    System.out.println(overlap("192.168.0.1/24", "192.168.0.0/24"));
}

@nacx Thanks, this was helpful.