MinimumSwaps2.py

#!/bin/python3

import math
import os
import random
import re
import sys

# Complete the minimumSwaps function below.
def minimumSwaps(arr):
    minSwap = 0
    for i in range(len(arr)):
        while arr[i] != i+1:
            temp = arr[i]
            arr[i] = arr[temp-1]
            arr[temp-1] = temp
            minSwap += 1
    return minSwap

if __name__ == '__main__':
    fptr = open(os.environ['OUTPUT_PATH'], 'w')

    n = int(input())

    arr = list(map(int, input().rstrip().split()))

    res = minimumSwaps(arr)

    fptr.write(str(res) + '\n')

    fptr.close()

MinimumSwaps2.txt

You are given an unordered array consisting of consecutive integers = [1, 2, 3, ..., n] without any duplicates. You are allowed to swap any two elements. You need to find the minimum number of swaps required to sort the array in ascending order.

For example, given the array arr = [7,1,3,2,4,5,6] we perform the following steps:

i   arr                         swap (indices)
0   [7, 1, 3, 2, 4, 5, 6]   swap (0,3)
1   [2, 1, 3, 7, 4, 5, 6]   swap (0,1)
2   [1, 2, 3, 7, 4, 5, 6]   swap (3,4)
3   [1, 2, 3, 4, 7, 5, 6]   swap (4,5)
4   [1, 2, 3, 4, 5, 7, 6]   swap (5,6)
5   [1, 2, 3, 4, 5, 6, 7]
It took 5 swaps to sort the array.

Function Description

Complete the function minimumSwaps in the editor below. It must return an integer representing the minimum number of swaps to sort the array.

minimumSwaps has the following parameter(s):

arr: an unordered array of integers