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$("h1, h2, h3, h4, span, p").text(function(index, text){ return text.replace(/o/ig, "🎃").replace(/a/ig, "💀"); }); |
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{ | |
"font_face": "Consolas", | |
"font_size": 8, | |
"ignored_packages": | |
[ | |
"Vintage" | |
], | |
"tab_size": 4, | |
"translate_tabs_to_spaces": true | |
} |
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Array.prototype.flatten = function() { | |
return this.reduce(function(prev, cur) { | |
var more = [].concat(cur).some(Array.isArray); | |
return prev.concat(more ? cur.flatten() : cur); | |
},[]); | |
}; | |
String.prototype.format = function () { | |
var content = this; | |
// regular for loop would probably be more efficient than the forEach |
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from math import ceil, floor, log10 | |
def pascal(rows, p_row): | |
print(" "*rows+ " ".join([" "*(3-floor(log10(x))) + str(x) for x in p_row])) | |
if rows: | |
p_row.append(1) | |
for i in reversed(range(ceil(len(p_row)/2)-1)): | |
p_row[i+1] += p_row[i] | |
p_row[-(i+2)] = p_row[i+1] | |
pascal(rows-1, p_row) |