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Given an array of time intervals (start, end) for classroom lectures (possibly overlapping), find the minimum number of rooms required. For example, given [(30, 75), (0, 50), (60, 150)], you should return 2.
# Sort jobs by finish times so that f1<=f2<=..<=fn
# 𝐴 ← βˆ…, π‘™π‘Žπ‘ π‘‘ ← 0
# for 𝑗 ← 1 to 𝑛
# if 𝑠𝑗 β‰₯ π‘™π‘Žπ‘ π‘‘ then 𝐴 ← 𝐴 βˆͺ {𝑗}, π‘™π‘Žπ‘ π‘‘ ← 𝑓𝑗
# return οΏ½
require('set')
def minimum_room_no(times)
times = times.sort {|a,b| a[1] <=> b[1]}
a = Set.new
last = 0
times.each do |t|
if t[0] >= last
a = a | [t].to_set()
last = t[1]
end
end
return a.length
end
times = [[30, 75], [0, 50], [60, 150]]
puts "Minimum Room Number: #{minimum_room_no(times)}"
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