Store Credit

aline.py

credit = '\n'.join('Case #{}: {} {}'.format(test+1, *[i[0]+1 for c in (lambda x, y: (x,))(int(input()), int(input())) for i, l in (lambda x: zip(enumerate(e for e in x), [x for e in x]))([int(v) for v in input().split()]) for j in enumerate(l) if i[1] + j[1] == c and i[0] != j[0]]) for test in range(int(input())))

bookmark.md

Store Credit

According to this Code Jam problem, I try to made it in one line.

code.py

credit = '\n'.join(
             'Case #{}: {} {}'.format(
                 test+1,
                 *[i[0]+1 for c in (lambda x, y: (x,))(int(input()), int(input()))    # init credit
                     for i, l in (lambda x: zip(
                         enumerate(e for e in x),                                     # 1st item
                         [x for e in x]))([int(v) for v in input().split()])
                     for j in enumerate(l)                                            # 2nd item
                     if i[1] + j[1] == c and i[0] != j[0]])                       # check if 1st + 2nd
                 for test in range(int(input())))                                 # use all the credit.

LICENSE.txt

            DO WHAT THE FUCK YOU WANT TO PUBLIC LICENSE
                    Version 2, December 2004

 Copyright (C) 2012 Nattawut Phetmak <http://about.me/neizod>

 Everyone is permitted to copy and distribute verbatim or modified
 copies of this license document, and changing it is allowed as long
 as the name is changed.

            DO WHAT THE FUCK YOU WANT TO PUBLIC LICENSE
   TERMS AND CONDITIONS FOR COPYING, DISTRIBUTION AND MODIFICATION

  0. You just DO WHAT THE FUCK YOU WANT TO.

package.json

{
  "name": "store_credit",

  "description": "find pair of item that use up all credit.",

  "keywords": [
    "math",
    "pairing",
    "codejam"
  ]
}

test.py

credit = '\n'.join('Case #{}: {} {}'.format(test+1, *[i[0]+1 for c in (lambda x, y: (x,))(int(input()), int(input())) for i, l in (lambda x: zip(enumerate(e for e in x), [x for e in x]))([int(v) for v in input().split()]) for j in enumerate(l) if i[1] + j[1] == c and i[0] != j[0]]) for test in range(int(input())))

# stdin:
# 3
# 100
# 3
# 5 75 25
# 200
# 7
# 150 24 79 50 88 345 3
# 8
# 8
# 2 1 9 4 4 56 90 3

expected = '''Case #1: 2 3
Case #2: 1 4
Case #3: 4 5'''
print(expected)

print(credit)