Created
September 20, 2016 05:32
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#include <bits/stdc++.h> | |
#define _for(i,a,b) for (int i=(a),_b_=(b),_d_=(a<b?1:-1);i!=_b_;i+=_d_) | |
#define _it(i,v) for (typeof((v).begin()) i = (v).begin(); i != (v).end(); ++i) | |
#define _all(v) v.begin(), v.end() | |
using namespace std; | |
typedef long long LL; | |
typedef unsigned long long ULL; | |
template<typename T> vector<T> &operator += (vector<T> &v, T x) {v.push_back(x);return v;} | |
struct P { | |
LL t,m; | |
}; | |
bool operator< (const P &a, const P &b) { | |
LL t = __gcd(a.m,b.m); | |
return b.m/t*a.t < a.m/t*b.t; | |
} | |
bool operator== (const P &a, const P &b) { | |
LL t = __gcd(a.m, b.m); | |
return b.m/t*a.t == a.m/t*b.t; | |
} | |
bool operator!= (const P &a, const P &b) { | |
return !(a==b); | |
} | |
P operator+ (const P &a, const P &b) { | |
P p = { | |
a.t + b.t, | |
a.m + b.m | |
}; | |
LL t = __gcd(p.t, p.m); | |
p.t /= t; p.m /= t; | |
return p; | |
} | |
void solve() { | |
P l={0,1},r={1,0},a,b={1,1}; | |
cin >> a.t >> a.m; | |
while (a!=b) { | |
if (b<a) { | |
cout << 'R'; | |
P t = b; | |
b = b+r; | |
l = t; | |
} else { | |
cout << 'L'; | |
P t = b; | |
b = b+l; | |
r = t; | |
} | |
} | |
} | |
int main(){ | |
#ifdef NGOBACH | |
freopen("input.txt","r",stdin); | |
// freopen("output.txt","w",stdout); | |
#endif | |
ios_base::sync_with_stdio(0); | |
cin.tie(0); | |
solve(); | |
} | |
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Cách code của thầy rất hay.. e cảm ơn những bài post của thầy... và mong thầy có thể nói rõ cho e cách làm bài http://vn.spoj.com/problems/TCDFZ/ với ạ? e chân thành cảm ơn...