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Small programming challenges
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// Given a boolean matrix, and a point (x, y) you need to | |
// change the values for all the adjacent (x1, y1) such that |x-x1| + |y-y1| = 1 | |
// (neighbors with adjacent side) | |
#define flip!(x, y) matrix[x][y] = !matrix[x][y] | |
int xs = {-1, 0, 1, 0}; | |
int ys = {0, 1, 0, -1}; | |
bool visited[D+1][D+1]; | |
bool matrix[D+1][D+1]; | |
bool inside(x, y){ | |
return (x >= 0) && (x < D) && (y >= 0) && (y < D); | |
} | |
void flip_it(int x, int y){ | |
visited[x][y] = true; | |
for(int i=0; i<4;++i){ | |
int nx = x + xs[i]; | |
int ny = y + ys[i]; | |
if(inside(nx, ny) && a[x][y] == a[nx][ny] && !visited[nx][ny]){ | |
flip_it(nx, ny); | |
} | |
} | |
flip!(x, y); | |
} |
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template<typename T> | |
void combine(vector<T> &s, int low, int middle, int high){ | |
queue<int> left, right; | |
for(int i=low; i <= middle; ++i) left.push(s[i]); | |
for(int i=middle + 1; i <= high; ++i) right.push(s[i]); | |
int index = low; | |
while(left.size() && right.size()){ | |
if(left.front() < right.front()){ | |
s[index++] = left.front(); | |
left.pop(); | |
}else{ | |
s[index++] = right.front(); | |
right.pop(); | |
} | |
} | |
while(left.size()) { s[index++] = left.front(); left.pop(); } | |
while(right.size()){ s[index++] = right.front(); right.pop();} | |
} | |
void merge_sort(vector<T> &s, int low, int high){ | |
int middle = (low + high) / 2; | |
if(low >= high) return; | |
merge_sort(s, low, middle); | |
merge_sort(s, middle + 1, high); | |
combine(s, low, middle, high); | |
} |
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template <typename T> | |
void dutch_flag_partition(vector<T> &A, int from, int to){ | |
/** | |
* bottom group: A[0..smaller - 1] | |
* middle group: A[smaller..equal - 1] | |
* unclassified: A[equal..larger - 1] | |
* top group: A[larger..A.size - 1] | |
**/ | |
int pivot_index = (from + to) / 2; | |
int pivot = A[pivot_index]; | |
if(from >= to) return; | |
int smaller = from, equal = from, larger = to - 1; | |
while(equal <= larger){ | |
int element = A[equal]; | |
if(element < pivot){ | |
swap(A[equal++], A[smaller++]); | |
}else if(element == pivot){ | |
equal++; | |
}else{ | |
swap(A[equal], A[larger--]); | |
} | |
} | |
dutch_flag_partition(A, from, smaller); | |
dutch_flag_partition(A, equal, to); | |
} |
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// Print a matrix in spiral order | |
vector<vector<int> > a(7, vector<int>(7, 0)); | |
void do_ring(int ring, int n){ | |
int i, j; | |
i = j = ring; | |
for(j = ring; j < n - ring ; ++j) cout << a[i][j] << " "; | |
j = n - ring - 1; | |
for(i = ring + 1; i < n - ring; ++i) cout << a[i][j] << " "; | |
i = n - ring - 1; | |
for(j = n - ring - 2; j >= ring; --j) cout << a[i][j] << " "; | |
j = ring; | |
for(i = n - ring - 2; i > ring; --i) cout << a[i][j] << " "; | |
} | |
int main(){ | |
for(int ring=0;ring < ceil(a.size() / 2.0); ++ring) | |
do_ring(ring, a.size()); | |
} |
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