Generate Hexadecimal Pattern: random.randrange()

gen_hex_patt.py

#!/bin/python3
'''
generate password based on hex pattern
93b44021-a479-5fc2-4037-08b690031c73
xxxx-xx-xx-xx-xxxxxx
'''
from random import randrange

patt = [4, 2, 2, 2, 6]
hex_sets = []

for p in patt:
    hex_sets.append(''.join([hex(randrange(0, 255))[2:] for a in range(p)]))

print('-'.join(hex_sets))

The purpose for this script was to generate any pattern of hexdecimal octets for specific random passwords

93b44021-a479-5fc2-4037-08b690031c73 becomes an example of a pseudo-randomly generated hex pattern for password creation but values in patt can be changed in order to suit any particular pattern—also add to the list; increase the number of values.

xxxx-xx-xx-xx-xxxxxx notice how this pattern example represents the actual values in patt, which are based on the number of octets needed, instead of the total value of hexits. In other words, the hexadecimal octet a4 contains the hexits a and 4.

Even though patt contains [4, 2, 2, 2, 6] for my original purpose, it could be changed to [4, 3, 4, 3, 6, 5] for your purpose, for example.