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#include <iostream> | |
#include <iomanip> | |
#include <fstream> | |
#include <cstdlib> | |
#include <vector> | |
using namespace std; | |
vector<double> x, y; | |
int get_file(string filename) { | |
double i, j; | |
ifstream file(filename); | |
while (file >> i >> j) { | |
x.push_back(i); | |
y.push_back(j); | |
} | |
return x.size(); | |
} | |
int find_index(double xval) { | |
for (int j = 0; true; j++) { | |
if (xval >= x[j] && xval <= x[j+1]) | |
return j; | |
} | |
} | |
int main() { | |
ofstream output("a17-res.dat"); | |
int n = get_file("a16-interpol.dat"); | |
vector <double> alpha(n), beta(n), gamma(n), delta(n), lambda(n+1), mu(n+1), d(n+1), M(n+1); | |
mu[0] = 2.0; | |
for (int j = 1; j < n; j++) { | |
lambda[j] = (x[j+1] - x[j]) / (x[j+1] - x[j-1]); | |
mu[j] = (x[j] - x[j-1]) / (x[j+1] - x[j-1]); | |
d[j] = (6 / (x[j+1] - x[j-1])) * ((y[j+1] - y[j]) / (x[j+1] - x[j]) - (y[j] - y[j-1]) / (x[j] - x[j-1])); | |
} | |
for (int i = 1; i <= n; i++) { | |
double f = -mu[i] / mu[i-1]; | |
mu[i] = 2 + f * lambda[i-1]; | |
d[i] = d[i] + f * d[i-1]; | |
} | |
M[n] = d[n] / mu[n]; | |
for (int j = n - 1; j >= 0; j--) { | |
M[j] = (d[j] - (lambda[j] * M[j+1])) / mu[j]; | |
alpha[j] = y[j]; | |
beta[j] = (y[j+1] - y[j]) / (x[j+1] - x[j]) - ((2 * M[j] + M[j+1]) * (x[j+1] - x[j]) / 6); | |
gamma[j] = M[j] / 2; | |
delta[j] = (M[j+1] - M[j]) / (6 * (x[j+1] - x[j])); | |
} | |
for (double xval = x.front(); xval < x.back(); xval += (x.back() - x.front()) / 300) { | |
int j = find_index(xval); | |
double D = xval - x[j]; | |
double S = alpha[j] + beta[j] * D + gamma[j] * D * D + delta[j] * D * D * D; | |
cout << xval << " " << S << endl; | |
output << xval << " " << S << endl; | |
} | |
} |
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#include <iostream> | |
#include <vector> | |
#include <map> | |
#include <numeric> | |
using namespace std; | |
map<char, int> M = {{'M', 1000}, {'D', 500}, {'C', 100}, {'L', 50}, {'X', 10}, {'V', 5}, {'I', 1}}; // requires C++11 | |
int calc(string s) { | |
vector <int> n; | |
for (int i = 0; i < s.size(); i++) { | |
n.push_back(M[toupper(s[i])]); | |
n[i-1] *= (n[i-1] < n[i]) ? -1 : 1; | |
} | |
return accumulate(n.begin(), n.end(), 0); | |
} | |
int main() { | |
string s; | |
cout << "Eingabe: "; | |
cin >> s; | |
cout << "Ausgabe: " << calc(s) << endl; | |
} |
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