Created
October 26, 2020 05:21
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Challenges from https://medium.com/better-programming/practicing-recursion-with-7-algorithm-challenges-7ffdd634557
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from functools import lru_cache | |
def flip(text): | |
if not text: | |
return '' | |
return text[-1] + flip(text[:-1]) | |
def addingUpTo(numbers, idx): | |
try: | |
if idx >= 0: | |
return numbers[idx] + addingUpTo(numbers, idx-1) | |
else: | |
return 0 | |
except IndexError: | |
return addingUpTo(numbers, idx-1) | |
def maxOf(numbers): | |
if numbers: | |
submax = maxOf(numbers[:-1]) | |
if submax is None: | |
return numbers[-1] | |
return max(numbers[-1], submax) | |
else: | |
return None | |
def includesNumber(numbers, num): | |
if numbers: | |
if numbers[-1] == num: | |
return True | |
else: | |
return includesNumber(numbers[:-1], num) | |
else: | |
return False | |
def isPalindrome(text): | |
if text: | |
return text[0] == text[-1] and isPalindrome(text[1:-1]) | |
else: | |
return True | |
@lru_cache | |
def permutations(text): | |
if len(text) >= 2: | |
p = [] | |
for idx, letter in enumerate(text): | |
subtext = text[0:idx] + text[idx+1:] | |
subps = permutations(subtext) | |
for subp in subps: | |
if not (letter + subp) in p: | |
p.append(letter + subp) | |
return p | |
else: | |
return [text] | |
@lru_cache | |
def fib(n): | |
if n == 0 or n == 1: | |
return n | |
return fib(n-1) + fib(n-2) |
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