Created
August 7, 2019 08:42
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Solution for HackerRank challenge "Contacts" (https://www.hackerrank.com/challenges/contacts/problem)
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| #!/bin/python3 | |
| DEBUG = False | |
| import os | |
| import sys | |
| def trie_find(node, path): | |
| if not node.get(path[0]): | |
| return 0 | |
| if len(path) > 1: | |
| return trie_find(node[path[0]], path[1:]) | |
| else: | |
| return node[path[0]]['__count'] | |
| def trie_inc(node, path): | |
| if not node.get(path[0]): | |
| node[path[0]] = { '__count': 0 } | |
| node[path[0]]['__count'] = node[path[0]]['__count'] + 1 | |
| if len(path) > 1: | |
| trie_inc(node[path[0]], path[1:]) | |
| # | |
| # Complete the contacts function below. | |
| # | |
| def contacts(queries): | |
| trie = {} | |
| answers = [] | |
| for query in queries: | |
| if query[0] == 'add': | |
| trie_inc(trie, list(query[1])) | |
| else: | |
| answers.append(trie_find(trie, list(query[1]))) | |
| return answers | |
| if __name__ == '__main__': | |
| if DEBUG: | |
| queries = [line.strip().split() for line in open("in.txt", 'r')][1:] | |
| result = contacts(queries) | |
| for line in result: | |
| print(line) | |
| else: | |
| fptr = open(os.environ['OUTPUT_PATH'], 'w') | |
| queries_rows = int(input()) | |
| queries = [] | |
| for _ in range(queries_rows): | |
| queries.append(input().rstrip().split()) | |
| result = contacts(queries) | |
| fptr.write('\n'.join(map(str, result))) | |
| fptr.write('\n') | |
| fptr.close() |
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