is_palindrome.js

// 1234567
// racecar
// 0123456
// >>>X<<< close in on it, only need half the length of word loopage

function is_palindrome(word) {
    
    var outcome = true;
    for(i = 0; i <= (word.length / 2); i++) {
        
        //console.log("Comparing " + word[i] + " and " + word[word.length - 1 - i] + "." );
        
        // always true for palindromes
        if(word[i] != word[word.length - 1 - i]) {
            outcome = false;
            break;  
        }
        
    }
    
    return outcome;

}

Was asked this for a whiteboarding interview once, wanted to give it an honest shot. Is there any more efficient way to do this?