Created
April 1, 2017 10:16
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Sort index in pandas
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In [297]: d = {0: {'foo': {'a': 12.68, 'b': 54.44, 'c': 83.98}, | |
...: 'bar': {'a': 11.73, 'b': 53.34, 'c': 82.93}}, | |
...: 2: {'foo': {'a': 11.12, 'b': 57.99, 'c': 81.05}, | |
...: 'bar': {'a': 10.05, 'b': 56.12, 'c': 80.01}}, | |
...: 1: {'foo': {'a': 13.41, 'b': 54.32, 'c': 82.74}, | |
...: 'bar': {'a': 12.77, 'b': 53.15, 'c': 82.01}}} | |
In [298]: ds = (pd.DataFrame.from_dict(d, orient='index') | |
...: .stack().apply(pd.Series) | |
...: .rename_axis(['experiment', 'setup'])) | |
In [299]: ds.sort_index(level = 0, inplace = True) | |
In [300]: ds | |
Out[300]: | |
a b c | |
experiment setup | |
0 foo 12.68 54.44 83.98 | |
bar 11.73 53.34 82.93 | |
1 foo 13.41 54.32 82.74 | |
bar 12.77 53.15 82.01 | |
2 foo 11.12 57.99 81.05 | |
bar 10.05 56.12 80.01 |
Sorting 'foo' and 'bar' seems to be a special case. Try 'f' instead of 'foo' and 'b' instead of 'bar'.
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Now I start to see the weiredness ... it looks like 'foo' and 'bar' is sorted like 'foo' < 'bar'. Why should that be the case? I tried to set ascending = False, here it becomes even more obvious ...