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input | |
1 - 2 | |
1 - 3 | |
2 - 3 | |
2 - 4 | |
3 - 1 | |
3 - 2 | |
4 - 1 | |
4 - 2 | |
sort: | |
1 - 2 | |
1 - 3 | |
2 - 3 | |
2 - 4 | |
1 - 3 | |
2 - 3 | |
1 - 4 | |
2 - 4 | |
prob | |
1-4 | |
2-4 | |
required | |
1 - 3 | |
2 - 3 | |
3 - 2 | |
4 - 2 |
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let data = { | |
links: [{ | |
from: 1, | |
to: 2, | |
}, { | |
from: 1, | |
to: 3, | |
}, { | |
from: 2, | |
to: 3, | |
}, { | |
from: 2, | |
to: 4, | |
}, | |
{ | |
from: 3, | |
to: 1, | |
}, { | |
from: 3, | |
to: 2, | |
}, { | |
from: 4, | |
to: 1, | |
}, { | |
from: 4, | |
to: 2, | |
} | |
] | |
} | |
var keyVals = []; | |
var influencers = []; | |
for (let index = 0; index < data.links.length; index++) { | |
const element = data.links[index]; | |
var pairs = []; | |
pairs.push(element.from, element.to); | |
pairs.sort((a, b) => a - b); | |
keyVals.push({ id: pairs[0], value: pairs[1] }); | |
} | |
keyVals.sort((a, b) => a.id - b.id); | |
console.log(keyVals); | |
for (let index = 0; index < keyVals.length; index++) { | |
if (!influencers.find((influencer) => influencer.id === keyVals[index].id)) { | |
influencers.push({ id: keyVals[index].id, count: 1 }); | |
} else { | |
influencers.find( | |
(influencer) => influencer.id === keyVals[index].id | |
).count += 1; | |
} | |
} | |
console.log(influencers); |
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Implement a function that returns an object showing how many unique connections each user has. |
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