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My aipo 2013 solutions
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#include <stdio.h> | |
#include <string.h> | |
#include <stdbool.h> | |
unsigned t(char a){ | |
return (unsigned)(a-48); | |
} | |
int main(void){ | |
char d[13]; | |
unsigned count = 0; | |
char tmp; | |
bool a, doom = false; | |
unsigned i; | |
unsigned to; | |
unsigned gs = 0; //Gropus | |
unsigned gcount = 0; | |
//Spaghetti code a'la C | |
while((tmp = getchar()) != EOF){ | |
if(tmp != '-' && tmp != ' ' && tmp != '\n'){ | |
d[count++] = tmp; | |
}else if(tmp != '\n'){ | |
if(gcount==count){ | |
doom = true; | |
} | |
if(gs==0){ | |
if(count!=3){ | |
doom = true; | |
} | |
} | |
gcount = count; | |
++gs; | |
} | |
if(tmp == '\n'){ | |
if(d[0]=='9' && d[1]=='7' && (d[2]=='8' || d[2]=='9') && gs==4 && !doom && count == 13){ | |
a = false; | |
to = 0; | |
i = 0; | |
for(; i< 12; ++i, a = !a){ | |
if(a){ | |
to += t(d[i])*3; | |
}else{ | |
to += t(d[i]); | |
} | |
} | |
printf("%u\n",((10 - (to % 10)) % 10 ) == t(d[12]) ? 1 : 0 ); | |
}else{ | |
printf("0\n"); | |
} | |
count = 0; | |
gs = 0; | |
doom = false; | |
} | |
} | |
return 0; | |
} |
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#include <stdio.h> | |
#include <math.h> | |
#include <stdbool.h> | |
//Over-complicated but I was debugging. Blame it on Gary | |
bool appToParis(unsigned self[3][2], unsigned len, unsigned val1, unsigned val2){ | |
unsigned i = 0; | |
for(i = 0; i<len; ++i){ | |
if((self[i][0] == val1 && self[i][1] == val2) || (self[i][0] == val2 && self[i][1] == val1)){ | |
return false; | |
} | |
} | |
self[len][0] = val1; | |
self[len][1] = val2; | |
return true; | |
} | |
int main(void){ | |
unsigned num; //to be found | |
unsigned found = 0; //found already | |
unsigned total; //resukls to check | |
unsigned first; //x | |
float tmp; //sqrt res | |
unsigned last = 0; //last num | |
unsigned lastn = 0; //number itself | |
unsigned pairs[3][2]; | |
unsigned pairl = 0; | |
scanf("%u",&num); | |
for(total = 3; found < num; ++total){ | |
for(first = 3; first < total; ++first){ | |
tmp = sqrt(total*total - first*first); | |
if((int)tmp == tmp){ | |
if(lastn == total){ | |
pairl += appToParis(pairs, pairl, first, (unsigned)tmp); | |
if(pairl > 1){ | |
//printf("\t%u. (%u, %f, %u)\n",found, first,tmp,total); | |
///printf("%u^2 + %f^2 = %u^2\n",first,tmp,total); | |
printf("%u\n",total); | |
break; | |
} | |
}else{ | |
++found; | |
lastn = total; | |
pairl = 0; | |
last = 0; | |
} | |
//printf("\t%u. (%u, %f, %u)\n",found, first,tmp,total); | |
} | |
} | |
} | |
return 0; | |
} |
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#include <stdio.h> | |
#include <stdlib.h> | |
#define uns unsigned | |
int comp(uns *a, uns *b){ | |
return (*a) > (*b); | |
} | |
int main(void){ | |
//get length | |
uns len, *arr = 0, i; | |
scanf("%u",&len); | |
//and allocate | |
arr = malloc(sizeof(uns)*len); | |
//and take down | |
for(i = 0; i< len; ++i){ | |
scanf("%u", &(arr[i])); | |
} | |
//#arr = len | |
qsort(arr,len,sizeof(uns),*comp); | |
uns atmid, a, b, sol = 0; | |
for(atmid = 0; atmid < len; ++atmid){ | |
for(a = 0; a <= atmid; ++a){ | |
for(b = atmid; b < len; ++b){ | |
//How it that failing! All conditions should be met | |
if(a != b && (arr[a]+arr[b])/2==arr[atmid] && (arr[a]+arr[b])%2==0){ | |
++sol; | |
} | |
} | |
} | |
} | |
printf("%u\n", sol); | |
//don't forgte to free | |
free(arr); | |
return 0; | |
} |
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