Created
May 9, 2017 08:00
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CodeAcademy Python project: DNA Analysis
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| sample = ['GTA','GGG','CAC'] | |
| def read_dna(dna_file): | |
| dna_data = "" | |
| with open(dna_file, "r") as f: | |
| for line in f: | |
| dna_data += line | |
| return dna_data | |
| def dna_codons(dna): | |
| codons = [] | |
| for i in range(0, len(dna), 3): | |
| if (i + 3) < len(dna): | |
| codons.append(dna[i:(i + 3)]) | |
| return codons | |
| def match_dna(dna): | |
| matches = 0 | |
| for codon in dna: | |
| if codon in sample: | |
| matches += 1 | |
| return matches | |
| def is_criminal(dna_sample): | |
| dna_data = read_dna(dna_sample) | |
| codons = dna_codons(dna_data) | |
| num_matches = match_dna(codons) | |
| if num_matches >= 3: | |
| print("There were %d codon matches in %s. Further investigation should be done") %(num_matches, dna_sample) | |
| else: | |
| print("There were only %d codon matches in %s. As the dna test clears this suspect of any allegations they can be freed") % (num_matches, dna_sample) | |
| is_criminal('suspect1.txt') | |
| is_criminal('suspect2.txt') | |
| is_criminal('suspect3.txt') | |
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Can you please send me the full ipython code of DNA matching?
[email protected] - this is my email id
send it as fast as possible please.