Created
July 7, 2020 02:08
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from typing import Tuple | |
import numpy as np | |
def n_union_and_intersection(a: np.ndarray, b: np.ndarray) -> Tuple[int, int]: | |
na = len(a) | |
nb = len(b) | |
ia = 0 | |
ib = 0 | |
if na == 0: | |
return (nb, 0) | |
if nb == 0: | |
return (na, 0) | |
cu = 2 if a[0] != b[0] else 1 | |
ci = 0 | |
ua = False | |
ub = False | |
while ia < na and ib < nb: | |
va = a[ia] | |
vb = b[ib] | |
eq = va == vb | |
lt = va < vb | |
gt = va > vb | |
ba = ia != na - 1 | |
bb = ib != nb - 1 | |
if eq: | |
if ua and ub: | |
cu += 1 | |
ci += 1 | |
else: | |
if ua: | |
cu += 1 | |
if ub: | |
cu += 1 | |
ua = False | |
ub = False | |
if eq: | |
if ba: | |
ua = True | |
if bb: | |
ub = True | |
elif lt and ba: | |
ua = True | |
elif gt and bb: | |
ub = True | |
elif ba: | |
ua = True | |
elif bb: | |
ub = True | |
if ua: | |
ia += 1 | |
if ub: | |
ib += 1 | |
if not ua and not ub: | |
break | |
return (cu, ci) |
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