Bundle an iterable into a list of tuples

bundle.py

"""
Bundles the iterable `l` into an iterable of tuples of length `x`, filling the last one with `f` if necessary.

Examples:

In [13]: list(bundle([1,2,3,4,5,6], 3, None))
Out[13]: [(1, 2, 3), (4, 5, 6)]

In [14]: list(bundle([1,2,3,4,5,6], 2, None))
Out[14]: [(1, 2), (3, 4), (5, 6)]

In [15]: list(bundle([1,2,3,4,5,6], 5, None))
Out[15]: [(1, 2, 3, 4, 5), (6, None, None, None, None)]

In [16]: list(bundle(range(9), 5, -12))
Out[16]: [(0, 1, 2, 3, 4), (5, 6, 7, 8, -12)]

In [17]: list(bundle('ojii', 3, '?'))
Out[17]: [('o', 'j', 'i'), ('i', '?', '?')]

"""
from itertools import izip_longest
bundle = lambda l,x,f:izip_longest(*[l[i::x] for i in range(x)], fillvalue=f)