Created
May 13, 2011 00:40
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Solution: Candy Splitting (Google Code Jam 2011 Qualification Round Problem C)
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import sys | |
fin = file(sys.argv[1]) | |
fout = open(sys.argv[2], 'w') | |
lines = fin.readlines() | |
tests = int(lines[0]) | |
candys0 = [map(int, line.split()) for line in lines] | |
def test0(a): return not (len(a) == 1) | |
candys = filter(test0, candys0) | |
data = [] | |
""" | |
no need to separate lists into piles! | |
patricks summation is exclusive or (XOR). | |
bitwise solution is very fast indeed. | |
""" | |
def xor0(a,b): return a^b | |
for candy in candys: | |
if (reduce(xor0, candy) == 0): | |
candy.sort() | |
data.append(sum(candy[1:])) | |
continue | |
data.append('NO') | |
for i in range(len(data)): | |
fout.write("Case #%s: %s\n" % (str(i+1), str(data[i]))) |
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