Created
May 20, 2011 13:29
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Solution: Alien Language (Google Code Jam 2009 Qualification Round Problem A)
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import string, sys | |
import re | |
""" | |
ab = {"a":1,"b":2,"c":3,"d":4,"e":5, | |
"f":6,"g":7,"h":8,"i":9,"j":10, | |
"k":11,"l":12,"m":13,"n":14,"o":15, | |
"p":16,"q":17,"r":18,"s":19,"t":20, | |
"u":21,"v":22,"w":23,"x":24,"y":25,"z":26} | |
""" | |
# alphabet map | |
ab = {} | |
i = 1 | |
for c0 in string.ascii_lowercase: | |
ab[c0] = i | |
i += 1 | |
# files | |
fin = file(sys.argv[1]) | |
fout = open(sys.argv[2], 'w') | |
lines = fin.readlines() | |
[l,d,n] = lines[0].split() | |
print l, d, n | |
def trunc(s0): | |
return s0.rsplit('\n')[0] | |
words = map(trunc, lines[1:int(d)+1]) | |
patterns = map(trunc, lines[int(d)+1:]) | |
# bitmaps | |
# slow for the large cases (5000 words, 500 patterns) | |
# can be improved with some sort of spatial indexing | |
# so we dont have to loop over entire alphabet ;) | |
# regex | |
def regex(s0): | |
s1 = s0.replace('(', '[') | |
s2 = s1.replace(')', ']') | |
return s2 | |
regexes = map(regex, patterns) | |
for i in range(len(regexes)): | |
count = 0 | |
for j in range(len(words)): | |
match = re.match(regexes[i], words[j]) | |
# print match | |
if match is not None: | |
count += 1 | |
fout.write("Case #%d: %d\n" % ((i + 1), count)) |
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