Created
May 24, 2011 15:33
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Solution: Square Tiles(Google Code Jam 2011 Round 1C Problem A)
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import sys | |
# files | |
fin = file(sys.argv[1]) | |
fout = open(sys.argv[2], 'w') | |
lines = fin.readlines() | |
tests = int(lines[0]) | |
# parse | |
indexes = [1] | |
wh = [] | |
for i in range(tests): | |
wh.append(map(int, lines[indexes[i]].split())) | |
indexes.append(indexes[i] + wh[i][0] + 1) | |
# tiles | |
tiles = [] | |
for i in range(tests): | |
index = indexes[i] | |
h = wh[i][0] | |
# w = wh[i][1] | |
tile = {} | |
for j in range(h): | |
tile[j] = lines[index + j + 1].split() | |
tiles.append(tile) | |
# switch | |
def blue(c0): | |
if c0 == '#': | |
return True | |
return False | |
def get(x0, y0, t0): | |
r0 = None | |
try: | |
r0 = t0[y0][0][x0] | |
except ValueError: | |
r0 = None | |
finally: | |
return r0 | |
def quad(x0, y0, t0): | |
xy = [(x0,y0),(x0+1,y0),(x0,y0+1),(x0+1,y0+1)] | |
q0 = [] | |
for p0 in xy: | |
q0.append(get(p0[0],p0[1],t0)) | |
return q0 | |
def switch(x0, y0, t0): | |
q0 = quad(x0, y0, t0) | |
if len(filter(lambda x: x, map(blue, q0))) == 4: | |
r0 = list(t0[y0][0]) | |
r1 = list(t0[y0+1][0]) | |
""" python str immutable | |
t0[y0][0][x0] = '/' | |
t0[y0][0][x0+1] = '\\' | |
t0[y0+1][0][x0] = '\\' | |
t0[y0+1][0][x0+1] = '/' | |
""" | |
r0[x0] = '/' | |
r0[x0+1] = '|' # backslash hack ;) | |
r1[x0] = '|' | |
r1[x0+1] = '/' | |
t0[y0][0] = "".join(r0) | |
t0[y0+1][0] = "".join(r1) | |
def output(t0, c0): | |
fout.write("Case #%d:\n" % c0) | |
imp = False | |
for y in t: | |
for x in range(len(t[y][0])): | |
if blue(t[y][0][x]): | |
imp = True | |
break | |
else: | |
continue | |
break | |
if (imp): | |
fout.write("Impossible") | |
else: | |
for y in t: | |
for x in range(len(t[y][0])): | |
if t[y][0][x] == '|': | |
fout.write('\\') | |
else: | |
fout.write(t[y][0][x]) | |
fout.write('\n') | |
fout.write('\n') | |
c = 1 | |
for t in tiles: | |
for y in t: | |
for x in range(len(t[y][0])): | |
if blue(t[y][0][x]): | |
switch(x, y, t) | |
output(t, c) | |
c += 1 |
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