sort_by_length_and_value.js

/**

Find the minimum value in an array of strings using a loop. For example, for this array:
  a=['my','name','is','john','doe'];
  
**/

const sortByLengthOnly = arr => arr.sort( (a, b) => a.length - b.length)

const sortByLengthAndValue = arr => arr.sort( (a, b) => { 
  if (a.length !== b.length) return a.length - b.length

  const longer = a.length > b.length ? a : b

  for (let idx in longer) {
    if (a[idx] === b[idx]) continue
    return a[idx] > b[idx]
  }
})

// case one
const a = ['my','name','is','john','doe']

const sortedByLengthOnlyA = sortByLengthOnly(a)

console.log(`Sorted by length only - ${sortedByLengthOnlyA}`)

const sortedByLengthAndValueA = sortByLengthAndValue(a)

console.log(`Sorted by length and values - ${sortedByLengthAndValueA}`)

// case 2 - to better demostrate sorting by value
const b = ['my','name', 'jakob','is','john', 'jake', 'doe']

const sortedByLengthOnlyB = sortByLengthOnly(b)

console.log(`Sorted by length only - ${sortedByLengthOnlyB}`)

const sortedByLengthAndValueB = sortByLengthAndValue(b)

console.log(`Sorted by length and values - ${sortedByLengthAndValueB}`)

/**
node v10.15.2 linux/amd64

// case 1
Sorted by length only - my,is,doe,name,john
Sorted by length and values - is,my,doe,john,name
// case 2
Sorted by length only - my,is,doe,name,john,jake,jakob
Sorted by length and values - is,my,doe,jake,john,name,jakob
**/