okplanbo/OneLineFizzBuzz.py

Created May 12, 2018 16:00

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Yet another solution to FizzBuzz in one line (Python3)

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OneLineFizzBuzz.py

for m in range(1,100): print("FizzBuzz" if (m%15==0) else"Fizz" if (m%3==0) else "Buzz" if (m%5==0) else m)

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