gistfile1.txt

gremlin> g = TinkerFactory.createClassic()
==>tinkergraph[vertices:6 edges:6]
gremlin> g.V.out.out.match('a',
gremlin>                g.of().as('b').out('created').as('a'),
gremlin>                g.of().as('a').in('knows').as('b'))
The provided traversal set contains a cycle due to 'a'
Display stack trace? [yN]
gremlin> 1+2
gremlin> 1+2
groovysh_parse: 5: expecting ')', found '1' @ line 5, column 1.
   1+2
   ^

1 error
Display stack trace? [yN]
gremlin> )
No signature of method: com.tinkerpop.gremlin.tinkergraph.process.graph.TinkerGraphTraversal.match() is applicable for argument types: (java.lang.String, com.tinkerpop.gremlin.tinkergraph.process.graph.TinkerTraversal, java.lang.Integer) values: [a, [StartStep@b, VertexStep(OUT)@a], 3]
Possible solutions: max(), wait(), min(), any(), mean(), path([Lgroovy.lang.Closure;)
Display stack trace? [yN]
gremlin> :clear
gremlin> 1+2
==>3