Delete all git remote tags

Remove all git tags

#Delete local tags.
git tag -l | xargs git tag -d
#Fetch remote tags.
git fetch
#Delete remote tags.
git tag -l | xargs -n 1 git push --delete origin
#Delete local tasg.
git tag -l | xargs git tag -d

nice, The "git tag -l | xargs git tag -d" in the example above might work better with "grep "

if any of the remote tags do not exist, the delete all approach bails out!

This will get the tags that are on the remote 'origin', then delete those tags:
git ls-remote --tags origin | cut -f 2 | xargs git push --delete origin

to delete refs as well:

git ls-remote origin | cut -f 2 | grep -iv head | xargs git push --delete origin

I didn't find a solution anywhere that didn't requre a single git push call per tag, so I came up with this variant, which - in my case - reduced the runtime from several hours to several seconds:

git push --delete origin $( git ls-remote --tags origin | awk '{print $2}' | grep -Ev "\^" | tr '\n' ' ')

Explanation

• git push --delete origin $(...): Deletes a tag (or multiple) on origin
• $( git ls-remote --tags origin | awk '{print $2}' | grep -Ev "\^" | tr '\n' ' '): Creates a space delimited string of all tags
  • git ls-remote --tags origin: Prints all tags on the remote origin
  • ... | awk '{print $2}' | ...: Only prints the second column of the previous command output
  • ... | grep -Ev "\^" | ...: Filters out unwanted refs/tags/mytag^{} variants (not sure where they come from)
  • ... | tr '\n' ' ': Converts the list into a space delimited string

It takes advantage of the fact that you can provide multiple tag names in a space delimited string, so it only invokes git delete once.

YMMV (use carefully):

deletes all (locally known) tags on remote named 'origin'

git push origin $(git tag -l --format=':%(refname)')

you may want to delete the tags locally also, or you might push them again:

git tag -d $(git tag -l)

Worked wonders thanks!