Created
November 14, 2019 15:03
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SQL получить пропущенные ID
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/* | |
есть записи в таблице, ID основной автоинкрементный ключ | |
нужен запрос, который выберет все записи, после которых нет следующей записи | |
Например для | |
123568 | |
получить | |
368 | |
*** | |
после 3 нет 4 | |
после 6 нет 7 | |
после 8 нет 9 | |
*/ | |
SELECT u.user_id | |
FROM ( SELECT s.user_id, @new_id := @new_id + 1 AS new_id | |
FROM ( SELECT @new_id := 1 ) i | |
JOIN ( SELECT r.user_id | |
FROM tubes.user_info r | |
WHERE r.user_id > 1 | |
ORDER BY r.user_id | |
) s | |
ORDER BY s.user_id | |
) u | |
WHERE u.user_id <> u.new_id | |
ORDER BY u.user_id |
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