Created
April 12, 2023 21:14
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You’re given two sorted integer arrays, nums1 and nums2, of size m and n, respectively. Your task is to return the median of the two sorted arrays. The overall run time complexity should be O(log(m+n)).
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| export function findMedian(nums1, nums2) { | |
| const totalLength = nums1.length + nums2.length; | |
| const leftHalfLength = Math.floor(totalLength / 2); | |
| const listA = nums1.length < nums2.length ? nums1 : nums2; | |
| const listB = nums1.length < nums2.length ? nums2 : nums1; | |
| let l = 0; | |
| let r = listA.length - 1; | |
| while (true) { | |
| let i = Math.floor((l + r) / 2); | |
| let j = leftHalfLength - i - 2; | |
| const leftA = listA[i] ?? -Infinity; | |
| const rightA = listA[i + 1] ?? Infinity; | |
| const leftB = listB[j] ?? -Infinity; | |
| const rightB = listB[j + 1] ?? Infinity; | |
| console.log( | |
| `[${listA.map((value, index) => { | |
| if (index === i) { | |
| return `${value} |`; | |
| } | |
| return value; | |
| })}]`, | |
| `[${listB.map((value, index) => { | |
| if (index === j) { | |
| return `${value} |`; | |
| } | |
| return value; | |
| })}]`, | |
| { i, j, l, r } | |
| ); | |
| if (leftA < rightB && leftB < rightA) { | |
| if (totalLength % 2 !== 0) { | |
| return Math.min(rightA, rightB); | |
| } | |
| return (Math.max(leftA, leftB) + Math.min(rightA, rightB)) / 2; | |
| } else if (leftA >= rightB) { | |
| r = i - 1; | |
| } else if (leftB >= rightA) { | |
| l = i + 1; | |
| } | |
| } | |
| } |
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