FizBuzz curry

Fuctional FizzBuzz in Ruby

f = proc{|string, num, x| x % num == 0 ? string : x}.curry
f3 = f.('Fizz',3)
f15 = f.('FizzBuzz',15)
f5 = f.('Buzz',5)
puts (1..100).map(&f15).map(&f5).map(&f3)

# and here's another approach

module Enumerable
  # map all elements for which the condition is true, leave the rest intact
  def map_if(cond)
    [].tap { |out| each { |e| cond.call(e) ? out << yield(e) : out << e} }
  end
end

f = proc{|i, x| x % i == 0}.curry
puts (1..100).map_if(f.(15)){'FizzBuzz'}.map_if(f.(3)){'Fizz'}.map_if(f.(5)){'Buzz'}

That's why they call it FUNctional programming!